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    spent every bloody holiday in the library, revised for hours, and except 6 marker this was **** for me. Even worse, apparently im the only person who found it hard, so high boundaries. a D if i'm lucky. I'll just take a gap year, then try get into an apprenticeship. AAB required for surry, physics won't be more than a C after this.
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    (Original post by Rahul.G)
    No it was not that. You had to use ln0.2 not ln0.8
    what was your answer?
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    (Original post by Rahul.G)
    No it was not that. You had to use ln0.2 not ln0.8
    **** , i think you might be right there lol
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    What did people get for the extra energy stored in the capacitor for question 1 section B
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    (Original post by duncant)
    got this but I got RC=28s? 45/-ln(0.2)
    yeah i got same. I think people missed the 'decrease BY 80% '
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    (Original post by Rahul.G)
    No it was not that. You had to use ln0.2 not ln0.8
    your right, how many marks was it?
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    (Original post by Cadherin)
    I got 200s for time constant?

    That was ok - some easy parts and some harder parts. I suspect grade boundaries will be normalish (62/75ish for 120 UMS).
    I think I might have got that
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    (Original post by RUNSran)
    yeah i got same. I think people missed the 'decrease BY 80% '
    Oh sh*t! Praying for low grade boundaries now
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    Boundary predictions? CAP?
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    (Original post by duncant)
    got this but I got RC=28s? 45/-ln(0.2)
    Ahh no you are right...i forgot to ln...silly me
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    (Original post by Beautywithabrain)
    I think I might have got that
    27.96 for time constant


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    (Original post by duncant)
    got this but I got RC=28s? 45/-ln(0.2)
    I got 28s too for the time constant, then around 59000 ohms I think for resistance

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    I worked out the energy of the capacitor by the area under the graph - is this valid?


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    (Original post by Beautywithabrain)
    I think I might have got that
    It will be that for the A*, 120 will be a bit higher I reckon
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    what did people say for the effect when that guy recorded only half of T? was it (1/4)g?
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    (Original post by Rahul.G)
    No it was not that. You had to use ln0.2 not ln0.8
    I got 200s (2sf) - actually, I think it's right.

    The question asked for a decrease TO 80% of its original value. (I'm almost certain).

    Thus e^(t/RC) = ln(1.25)=t/RC
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    (Original post by Cadherin)
    I got 200s (2sf) - actually, I think it's right.

    The question asked for a decrease TO 80% of its original value. (I'm almost certain).

    Thus e^(t/RC) = ln(1.25)=t/RC
    The question definitely specified decreased by 80%, standard AQA trick
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    (Original post by perpetua)
    Boundary predictions? CAP?
    62 is my guess for cap - there were some easier and some harder parts, so I would imagine it will be 4 marks higher than last year but 5 or so lower than June 13.

    Plus I would imagine the facility of the multiple choice is a lot lower than usual (maybe 60% rather than 67%).
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    (Original post by duncant)
    what did people say for the effect when that guy recorded only half of T? was it (1/4)g?
    Would it not be 4g because the gradient of the graph was 1/g?
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    (Original post by RUNSran)
    yeah i got same. I think people missed the 'decrease BY 80% '
    what if I wrote 30 secs !??? this was such a bad paper omds
 
 
 
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