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    Had an absolute mare for this and completely missed out the final question, for some reason thought it was the end of the paper after the 6 marker question up to the 4g one. Can anyone tell me how many marks question 5 was out of?
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    What do you think it will be for an A? around 50 marks or higher?
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    (Original post by Edpark123)
    Had an absolute mare for this and completely missed out the final question, for some reason thought it was the end of the paper after the 6 marker question up to the 4g one. Can anyone tell me how many marks question 5 was out of?
    i think it was 7 marks total. 2 then 3 then 2
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    (Original post by Datta10)
    I got 28s too for the time constant, then around 59000 ohms I think for resistance

    Posted from TSR Mobile
    I think I got sth similar. May have been 57000 ish. I remember I had a string of numbers and I was contemplating on whether or not I should keep it to 3 sf or sth. I left it as full integer at the end. Do you think that'll be all right?
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    (Original post by exmerelda)
    can anyone put up how they did the momentum of alpha question? i couldn't do it but i wanna see if i got any of the method marks
    E(alpha) +1/2NV^2 = E
    V=mv/N Substituting for V gives:
    E(alpha) + (1/2)(1/N)(m^2)(v^2) = E
    E(alpha) + (m/N)E(alpha) = E
    E(alpha)(N+m)/N = E
    E(alpha) = E(N/(N+m))
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    (Original post by Mango Milkshake)
    I wrote car takes longer to stop. No idea if its right
    I said that!!!
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    Section B last year was easier than this.
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    (Original post by Mango Milkshake)
    Was it suppose to touch the x-axis? mine didnt go all the way down but same shape

    ???
    Your second part of the graph isn't "curvey" enough. Remember 1/r^2 relationship. 2/3.
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    (Original post by marioman)
    My MC answers: DBADDCBBBCBCCACADACAADCBD

    Hopefully if a few contribute then we can get a rough marks scheme going.
    (Original post by Questioner1234)
    I said g would be 4x as big
    got 5.9x10^4 for something I think it was resistance
    28s for time constant
    1.15 x 10^-15 for something
    6.06X10^6 for something
    MCQs:
    D
    B
    B
    D
    D
    C
    D
    B
    B
    B
    B
    D
    C
    A
    B
    D
    B
    A
    C
    A
    A
    D
    C
    B
    D
    I got about 20 of them the same as you not sure what happened in the middle, thats where theyre different
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    (Original post by tanyapotter)
    Would saying that the constant magnetisation and demagnetisation of the electromagnet would waste energy be a valid disadvantage?

    Also, I accidentally put T^2 on the x axis and l on the y axis in the 6 marker - how many marks would I lose for that?
    I said (T/(2*pi))^2 on x axis, l on the y axis - which is right, as gradient is g.

    You would possibly lose 1 mark for not saying 'evaluate (T/(2*pi))^2.
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    (Original post by idk97)
    i feel u bro.... ive tried so flipping hard all year but after that i'll be surprised if i got a D
    Here here!
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    Was the direction from X to Y or Y to X
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    (Original post by Edpark123)
    Had an absolute mare for this and completely missed out the final question, for some reason thought it was the end of the paper after the 6 marker question up to the 4g one. Can anyone tell me how many marks question 5 was out of?
    After the 6 Marker there was a 3 Mark Question on about Time Period being miscalculated, 3 Marks on Electromagnetic Laws (maybe 4 pretty sure it was 3 though). A 3 marker on Lenz's Law and then finally a 2 Marker on Disadvantages of Electromagnetic Brakes so you have missed:

    About 11 Marks.
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    (Original post by kingaaran)
    I worked out the energy of the capacitor by the area under the graph - is this valid?


    Posted from TSR Mobile
    Well it's the same thing since the area of a triangle is 1/2 height(charge) x width (voltage) which is exactly as the formula E=1/2 QV on the formulae sheet you would have otherwise used.
    Did you remember to multiply 2.2 by 10^-6 ?
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    (Original post by kingaaran)
    Was the direction from X to Y or Y to X
    X to Y I think
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    Thought it was a really nice paper
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    (Original post by kingaaran)
    Was the direction from X to Y or Y to X
    I put x to y

    you?
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    (Original post by Questioner1234)
    Attachment 553448did everyones graph look like this????
    Minimum closer to Venus


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    I thought Y to X, they would both be positive so repulsion?
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    (Original post by CourtlyCanter)
    Well it's the same thing since the area of a triangle is 1/2 height(charge) x width (voltage) which is exactly as the formula on the formulae E=1/2 QV sheet you would otherwise have used.
    Did you remember to multiply 2.2 by 10^-6 ?
    How many marks was this question?


    Posted from TSR Mobile
 
 
 
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