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    What was the additional energy stored in the capacitor?
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    What grade/ums will 62/63 most probably be ?

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    (Original post by tanyapotter)
    stfu
    Cyber abuse TANYA POTTER
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    (Original post by splashywill)
    yeah I'm pretty sure it was 3F
    Isn't it an equipotential though?
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    (Original post by liverpool2044)
    why did i get 11 farads for the capacitance, i did q/v and worked out the gradient, surely i wont lose 3 or will there be a range of answers
    Hate to break it to you but 11 farads is huuuuge

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    (Original post by Squishy•)
    Isn't it an equipotential though?
    I got 3F

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    3.6x10^-5 J


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    (Original post by Euclidean)
    Hate to break it to you but 11 farads is huuuuge

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    micro i meant sorry
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    (Original post by study.bud)
    Sorry but no actually, F=EQ and E=V/d so F=VQ/d. So it would have been the reciprocal graph. The electric field strength is constant, not the force
    But D is no reciprocal either, as it touches both axes
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    (Original post by Yo12345)
    3.6x10^-5 J


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    @ rory


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    (Original post by Euclidean)
    I got 3F

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    I can't remember the question but i thought it asked something like the difference in force between x and y so whats the difference between closest point on the circle but isn't it the same because anywhere on a circle has the same distance from the centre and therefore the same force.
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    (Original post by perpetua)
    But D is no reciprocal either, as it touches both axes
    F= EQ - E is constant anf Q is constant, so surely F is constant?
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    (Original post by study.bud)
    Sorry but no actually, F=EQ and E=V/d so F=VQ/d. So it would have been the reciprocal graph. The electric field strength is constant, not the force
    The answer was definitely the graph showing constant force.
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    (Original post by Ginpls)
    Cyber abuse TANYA POTTER
    i will literally kill you gin
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    (Original post by Squishy•)
    I can't remember the question but i thought it asked something like the difference in force between x and y so whats the difference between closest point on the circle but isn't it the same because anywhere on a circle has the same distance from the centre and therefore the same force.
    It was the force between X and Y and you had to use Pythagoras to solve it, resulting in an answer of 3F
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    (Original post by tanyapotter)
    i will literally kill you gin
    ...............................
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    For the 2nd last multiple choice with the train through the magnetic field did anyone get C?
    (Original post by Yo12345)
    For the electromagnetic brakeI put:Advantage: A bigger brake force can be applied by making the magnetic field strongerDisadvantage: The brake would heat moreAre any of these right?Posted from TSR Mobile
    Yeah you could potentially get a larger brake force if you have a rather powerful electromagnetic. Disadvantage not sure, with a high resistance and current to get the high brake force the coil could heat up more.
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    (Original post by Vikingninja)
    For the 2nd last multiple choice with the train through the magnetic field did anyone get C?

    Yeah you could potentially get a larger brake force if you have a rather powerful electromagnetic. Disadvantage not sure, with a high resistance and current to get the high brake force the coil could heat up more.
    Thank you for replying


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    (Original post by marioman)
    The answer was definitely the graph showing constant force.
    There is a question is one of the past papers which asks you to find the force between two parallel points at the midpoint. Of course it's QV/D but most chose distractor QV/2D. The force is the same at all points between plates, it is uniform. So yeah it is.
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    (Original post by liverpool2044)
    why did i get 11 farads for the capacitance, i did q/v and worked out the gradient, surely i wont lose 3 or will there be a range of answers
    What points did you use on the graph? Since it was gradient I did the differences between two points. I got 8 micro farads.
 
 
 
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