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    For Section B the first question about finding the capacitance of the capacitor the gradient from the graph would have given 1/C
    right?

    I think I got 8 farads for that question I tried to find the gradient of the line then just used the reciprocal of the found gradient which got me 8 farads

    Please tell me if i did it correctly
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    (Original post by aelahi23)
    For Section B the first question about finding the capacitance of the capacitor the gradient from the graph would have given 1/C
    right?

    I think I got 8 farads for that question I tried to find the gradient of the line then just used the reciprocal of the found gradient which got me 8 farads
    It was micro farads but if you put the number 8 as the answer it was right because the symbol was micro farads. The gradient was C because it was Q/V, I got 8 micro farads from doing the gradient.
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    (Original post by Vikingninja)
    It was 8 micro farads but if you put the number 8 as the answer it was right because the symbol was micro farads.
    thanks man you saved me from a panic attack just now
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    (Original post by duncant)
    got this but I got RC=28s? 45/-ln(0.2)
    I got 28 seconds too
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    (Original post by Vikingninja)
    What points did you use on the graph? Since it was gradient I did the differences between two points. I got 8 micro farads.
    was volt or q on y axis
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    (Original post by liverpool2044)
    was volt or q on y axis
    It was Q on the y axis. I remember using 10.5 and 10 volts in the x axis for the gradient.
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    (Original post by Vikingninja)
    It was Q on the y axis. I remember using 10.5 and 10 volts in the x axis for the gradient.
    i used 3 volts diff and charge diff like 35x10-6
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    Anyone remember the resistance calculation? I got 28 has the time constant, was it 28/(406x10^-6) or something?
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    (Original post by liverpool2044)
    i used 3 volts diff and charge diff like 35x10-6
    Think I used for charge 86 and 82 (micro) and for volts 10.5 and 5, got 8 micro farads.
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    (Original post by Vikingninja)
    Think I used for charge 86 and 82 (micro) and for volts 10.5 and 5, got 8 micro farads.
    will there be a range, i tried to use biggest bit of graph possible, i cant see where i went wrong
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    (Original post by sandisiwe)
    ...............................
    help i am being ambushed by gin
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    Would I still get marks for describing a graph with L against T^2 instead of T^2 against L and with the equations rearranged appropriately?
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    did anyone get the time constant in 1c to be 201.6 something?
    Also, has there been any sort of unofficial mark scheme yet
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    (Original post by Datta10)
    What grade/ums will 62/63 most probably be ?
    A*.
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    (Original post by Datta10)
    What grade/ums will 62/63 most probably be ?

    Posted from TSR Mobile
    If you go off the fact most people found it slightly easier than last year's paper then maybe 115-117 UMS? Last year 62/63 was within the CAP I think
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    (Original post by harshman4477)
    Would I still get marks for describing a graph with L against T^2 instead of T^2 against L and with the equations rearranged appropriately?
    If your rearranging is correct then yes.

    (Original post by boyyo)
    did anyone get the time constant in 1c to be 201.6 something?Also, has there been any sort of unofficial mark scheme yet
    I think people who used V = 0.8V0 instead of V = 0.2V0 got 200 seconds.
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    will i get a mark for plating t with square root of l?
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    (Original post by ombtom)
    If your rearranging is correct then yes.



    I think people who used V = 0.8V0 instead of V = 0.2V0 got 200 seconds.
    yh i used 0.8Vo. Which one would be right, they cant both be can they
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    (Original post by mirko20000)
    will i get a mark for plating t with square root of l?
    Yeah, if you correctly stated how to find g from your gradient.
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    (Original post by kingaaran)
    I have the multiple choice paper: I'll post the answers on here in a bit


    Posted from TSR Mobile
    Can you make a separate thread so it doesnt get lost in here?
 
 
 
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