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# Find the position vector of the point of intersection of OT and PQ watch

1. PQ: 5i + 2j -9k + s(I -2j -3k)

Position vector of the point T: i+ 2j - k
2. The line OT can be written as some multiple t, times the position vector t, since it passes through the point 0i,0j,0k. From there set up simultaneous equations to find s and t that occur when PQ=OT

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3. please post a photo of the question
4. (Original post by TeeEm)
please post a photo of the question
6.iii
5. (Original post by _ocean_)

6.iii
What's your vector equation of the line OT?
6. (Original post by Zacken)
What's your vector equation of the line OT?
t( 1, 2, -1)
7. (Original post by _ocean_)
t( 1, 2, -1)
OT = t(1,2,-1)
P=(5,2,-9) and Q=(4,4,-6) -> PQ is (5,2,-9)+s(-1,2,3).
Hence set:
5-s=t
2+2s=2t
-9+3s=-t
Solve any 2 of these equations for s and t, then verify that they also satisfy the remaining equation.

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