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    PQ: 5i + 2j -9k + s(I -2j -3k)

    Position vector of the point T: i+ 2j - k
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    The line OT can be written as some multiple t, times the position vector t, since it passes through the point 0i,0j,0k. From there set up simultaneous equations to find s and t that occur when PQ=OT


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    please post a photo of the question
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    (Original post by TeeEm)
    please post a photo of the question
    6.iii
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    Zacken
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    (Original post by _ocean_)
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    6.iii
    What's your vector equation of the line OT?
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    (Original post by Zacken)
    What's your vector equation of the line OT?
    t( 1, 2, -1)
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    (Original post by _ocean_)
    t( 1, 2, -1)
    OT = t(1,2,-1)
    P=(5,2,-9) and Q=(4,4,-6) -> PQ is (5,2,-9)+s(-1,2,3).
    Hence set:
    5-s=t
    2+2s=2t
    -9+3s=-t
    Solve any 2 of these equations for s and t, then verify that they also satisfy the remaining equation.
 
 
 
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