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    Q: ABCD is base of a square pyramid of side 2 units and V is the vertex. The pyramid is symmetrical and of height 4 units. Calculate acute angle between AV and BC, giving your answer to 1 d.p.
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    AV = sqrt(17)
    Answer is 76.4. Not sure how to get it, this question is in the vectors sectors btw.
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    (Original post by TSRforum)
    Q: ABCD is base of a square pyramid of side 2 units and V is the vertex. The pyramid is symmetrical and of height 4 units. Calculate acute angle between AV and BC, giving your answer to 1 d.p.
    Here's my w/o: Name:  image.jpg
Views: 103
Size:  478.2 KB
    AV = sqrt(17)
    Answer is 76.4. Not sure how to get it, this question is in the vectors sectors btw.
    is this question on vector methods?
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    Dot Product, consider the vectors AV and AC.
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    (Original post by Argylesocksrox)
    Dot Product, consider the vectors AV and AC.
    What are the vectors AV and AC?
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    (Original post by TSRforum)
    What are the vectors AV and AC?
    The vector from A going to V, so V-A, and AC=C-A
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    (Original post by Argylesocksrox)
    The vector from A going to V, so V-A, and AC=C-A
    What is the vector of A, V & C? I don't know how to work it out

    Edit: I got the answer, did labelling at beginning wrong which gave me wrong vectors
 
 
 
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