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# Random trigonometry question help please. watch

1. Hi all,

Can anyone shed some light on how to go about solving this question?

(Question 7, for clarity).

Thank you!
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2. Attachment-1.pdf (278.7 KB, 94 views)
3. (Original post by londoncricket)
Hi all,

Can anyone shed some light on how to go about solving this question?

(Question 7, for clarity).

Thank you!
It's right angled, you should write down: immediately.

Furthermore, you can see that and .

Can you take it from here?
4. What level maths is this? (GCSE, C1, C2?
5. (Original post by Oblivion99)
What level maths is this? (GCSE, C1, C2?
Anybody doing GCSE should be able to do it.
6. (Original post by Zacken)
Anybody doing GCSE should be able to do it.
I don't get how tan of theta is a/b i thought it would be b/a because b is the opposite
7. (Original post by okey)
I don't get how tan of theta is a/b i thought it would be b/a because b is the opposite
Yep, that's correct. Thanks for pointing it out, must have gotten confused because of all the neck craning I was doing.
8. (Original post by Zacken)
It's right angled, you should write down: immediately.

Furthermore, you can see that and .

Can you take it from here?
Got it. Thanks!

(Original post by Oblivion99)
What level maths is this? (GCSE, C1, C2?
9. (Original post by Oblivion99)
Solved it. Its actually quite easy, yes. As someone stated above, just take note of the trigonometric identities (i.e cos 0 = a/b tan = b/c) and then you should be able to take it from here
These are both wrong.
10. (Original post by Zacken)
These are both wrong.
Can you provide me a step to step method onto solving this Q. Yes, ive actually flopped it
11. (Original post by Oblivion99)
Can you provide me a step to step method onto solving this Q. Yes, ive actually flopped it
Tell you what, I'll let the OP do it - it'll be good practice for him/her.

(Original post by londoncricket)
...
If he doesn't reply, then tag me in a bit and I will.
12. (Original post by Zacken)
Anybody doing GCSE should be able to do it.
hmmm ...
Attached Images

13. (Original post by Zacken)
Tell you what, I'll let the OP do it - it'll be good practice for him/her.

If he doesn't reply, then tag me in a bit and I will.
Its been an hour so
14. (Original post by Oblivion99)
Its been an hour so
If you look at the triangle and select the angle theta, then the adjacent over hypotenuse (i.e: cos) is:

The tangent is: (opposite over adjacent)

We also know it's a right angled triangle, so: .

Squaring and taking the reciprocal of cosine:

And also:

But since then, as required.

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