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# math watch

1. given that y=2^x solve that the equation
2^x+3(2^-x)=4
2. factor out 2^x and use logs, you'll have your answer quickly
3. Multiply both sides of equation by and you get a quadratic in disguise. Maybe let which may help you to notice that it is indeed a quadratic equation.
4. (Original post by alexschmalex)
Wouldn't work.
5. (Original post by TumiZN)
given that y=2^x solve that the equation
2^x+3(2^-x)=4
http://www.thestudentroom.co.uk/forumdisplay.php?f=38

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