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    given that y=2^x solve that the equation
    2^x+3(2^-x)=4
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    factor out 2^x and use logs, you'll have your answer quickly
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    Multiply both sides of equation by  2^x and you get a quadratic in disguise. Maybe let  p=2^x which may help you to notice that it is indeed a quadratic equation.
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    (Original post by alexschmalex)
    factor out 2^x and use logs, you'll have your answer quickly
    Wouldn't work.
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    (Original post by TumiZN)
    given that y=2^x solve that the equation
    2^x+3(2^-x)=4
    http://www.thestudentroom.co.uk/forumdisplay.php?f=38
 
 
 
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