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    So ive got this, how do I work it through to get cot(theta/2)? ( i know theyre both equivalent)

    Thanjs
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    Please post the question. Assuming you are correct (and nobody has any idea since you have not posted the question,). You might start by dividing top and bottom by \cos \theta
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    (Original post by JohnnyDavidson)
    So ive got this, how do I work it through to get cot(theta/2)? ( i know theyre both equivalent)

    Thanjs
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    Try writing \sin(\theta) and \cos(\theta) in terms of \sin(\frac{\theta}{2}) and \cos(\frac{\theta}{2}) using the double angle formulae.
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    (Original post by joostan)
    Try writing \sin(\theta) and \cos(\theta) in terms of \sin(\frac{\theta}{2}) and \cos(\frac{\theta}{2}) using the double angle formulae.
    Which is a whole lot better idea.
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    (Original post by nerak99)
    Please post the question. Assuming you are correct (and nobody has any idea since you have not posted the question,). You might start by dividing top and bottom by \cos \theta
    Tried to uploaf it just now, but got an error. My answer ive worked to, is equivalent to the correct answer though (so just need to work it trhough from where ive got to)
 
 
 
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