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    Hey there,

    I really need some help on 4(ii), 8(ii) and Q9 everything else was fine. I have looked all over the internet for a worked solution to this QP as the MS is so vague, so any help would be much appreciated.
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    (Original post by phatchewbaaca)
    Hey there,

    I really need some help on 4(ii), 8(ii) and Q9 everything else was fine. I have looked all over the internet for a worked solution to this QP as the MS is so vague, so any help would be much appreciated.
    What's troubling you about 8(ii)?

    a^x = 2b^x, take the logarithm base two of both sides (and use the power rule): x \log_2 a =  \log_2 2b^x

    Now use the fact that \log_a bc = \log_a b + \log_a c to expand \log_2 2b and making use of the rule \log_a a = 1 to simplify \log_2 2.

    That gets you x \log_2 a = \log_2 2 + \log_2 b^x = 1 + x\log_2 b

    Now collect all the x's on one side: x \log_2 a - x\log_2 b = 1.

    Factorise, do your shmoozy divide-sy and you're good to go.
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    (Original post by phatchewbaaca)
    Hey there,

    I really need some help on 4(ii), 8(ii) and Q9 everything else was fine. I have looked all over the internet for a worked solution to this QP as the MS is so vague, so any help would be much appreciated.
    4ii - remember that integrating between two x values finds the area bounded by those two x values and the two y values. You have two different curves there and you're asked to find the area between them, so can you see what to do with the integral of those two things?

    (You can also combine the equations in some way before integrating to give the same result).
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    (Original post by phatchewbaaca)
    Q9
    Which part of Q9? The first part should be easily derived by writing the differences in the form ar^(blah) - ar^(another blah) = 4 (other difference) and noticing that all the a's cancel easily.
 
 
 
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