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# ax + by + c = 0 Watch

1. Find the equation of the line through the point (3,-4) and parallel to the line through the points (2,-5) and (-1,3)

Give your answer in the form ax + by + c = 0
2. How far have you gotten with it?
4. find the gradient of the line going through these two points: (2,-5) and (-1,3)

use y-y1 = m (x -x1) with the gradient you just found and this point: (3,-4)
5. First tip: Find gradient of the point through (2, -5) and (-1, 3)
6. (Original post by Bethanyt5560)
Find the equation of the line through the point (3,-4) and parallel to the line through the points (2,-5) and (-1,3)

Give your answer in the form ax + by + c = 0
Gradient of line through (2,-5) and (-1,3) is (3+5)/(-1-2)=8/(-3)=-8/3.
Parallel lines have the same gradient so the gradient of the required line is -8/3.
Hence its equation is y+4=-8/3(x-3) -> Multiplying by 3, 3y+12=-8x+24 -> 8x+3y-12=0. (Hence a=8, b=3, c=-12).

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