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    I'm struggling a little with complex conjugate for this exponential function that has two components in the exponential.
    Name:  Screen Shot 2016-03-03 at 20.59.03.png
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    Im not sure weather the conjugate changes the sign of everything in the power or just the 'i' component?

    Could someone clarify weather C1 or C2 is correct?
    Thanks
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    (Original post by Walex12108)
    I'm struggling a little with complex conjugate for this exponential function that has two components in the exponential.
    Name:  Screen Shot 2016-03-03 at 20.59.03.png
Views: 429
Size:  13.4 KB
    Im not sure weather the conjugate changes the sign of everything in the power or just the 'i' component?

    Could someone clarify weather C1 or C2 is correct?
    Thanks

    Just the complex/i component. So C2 is.
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    (Original post by Walex12108)
    I'm struggling a little with complex conjugate for this exponential function that has two components in the exponential.
    Name:  Screen Shot 2016-03-03 at 20.59.03.png
Views: 429
Size:  13.4 KB
    Im not sure weather the conjugate changes the sign of everything in the power or just the 'i' component?

    Could someone clarify weather C1 or C2 is correct?
    Thanks
    For two complex numbers z_1,z_2 we have that \overline{z_1 z_2}=\bar{z_1}\bar{z_2} and if z is real, then \bar{z}=z. So in your case, we get:

    \overline{e^{ikx-x^2}} = \overline{ e^{ikx} e^{-x^2}} = \overline{ e^{ikx} } \times\overline{e^{-x^2} } = e^{-ikx} \times e^{-x^2} = e^{-ikx-x^2}

    assuming that x is real.
 
 
 
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