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    (Original post by klefki)
    Attachment 554089

    I got 55/12 for the area in q8, can someone tell me where I went wrong please? (sorry it's sideways)

    8*3=24 not 27
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    (Original post by klefki)
    Attachment 554089

    I got 55/12 for the area in q8, can someone tell me where I went wrong please? (sorry it's sideways)
    uno where u got 5/3 i got 14/3
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    (Original post by betapro)
    No it was just 8 i got that
    Yeah I've realised I was on about q5
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    (Original post by sonron202)
    8*3=24 not 27
    oh my god I'm an idiot ahahaha, hopefully only one or two marks for that
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    (Original post by klefki)
    Attachment 554089

    I got 55/12 for the area in q8, can someone tell me where I went wrong please? (sorry it's sideways)
    5th equal sign, 2/3(27) = 18 not 9 and 2/3(8) = 16/3 not 8/3 as well as what was said above
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    Guys help me about question 3 with the modulus question i got x=-1/3 and -1 but i wrote just in case i need y and also put y values will i still get full marks since that is just some extra info?
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    Anyone remember what we had to integrate for question 1?
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    (Original post by ComputerMaths97)
    5th equal sign, 2/3(27) = 18 not 9 and 2/3(8) = 16/3 not 8/3
    I can't believe out of that entire paper the mistake I made was multiplication
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    For the proof I said because n was a positive integer smallest value of 2^n + 1 is 3, as n increases 2^n + 1 or 2^n -1 must be a multiple of 3 ( they alternate each time n increases by 1), therefore if one of the factors is a multiple of 3 the whole equation must be divisible by 3
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    (Original post by Bealzibub)
    Anyone remember what we had to integrate for question 1?
    1 + cos(x/2) I think
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    Guys for the height question and volume for the first one, once you get 8 did you put units? I put 8 m^2 is that right, if not will ig et marked down?
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    The proof question:

    x^2n - 1 = (x^n - 1)(x^n + 1)
    When x = 2
    =>2^2n - 1 = (2^n - 1)(2^n + 1)

    2^n only has a prime factor of 2, meaning it is not divisible by 3.

    Additionally, since, for any 3 consecutive numbers, one of them must be divisible by three (since every 3rd number is a multiple of three)

    We can conclude that either 2^n - 1 OR 2^n OR 2^n + 1 is divisible by 3.

    Since we have proven 2^n is not divisible by 3.

    Either 2^n - 1 or 2^n + 1 must be divisible by 3

    Meaning (2^n - 1)(2^n + 1) = 2^2n - 1 is always divisible by 3, as required.
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    (Original post by Bealzibub)
    Beautiful paper, 71/72 for me, lowest 68/72
    This is what I remember:

    x^2n - 1\\

(x^n - 1)(x^n + 1)

    Odd * odd = odd so divisible by 3

    Area = 19/12
    ak+b = k-1
    4ln(4)-4
    Y=(1/2)x
    Gradient = 8 question 3
    dr/dt = 0.05 m per minute question 3ii
    P=(-4, -2)
    x = ln2 question 2
    x=-1 and x=-1/3
    dy/dx=1/(2cos2y)
    Ehy are people gettibg k-1 im dead sure its 0.5k -0.5Name:  IMG_20160621_115223.jpg
Views: 203
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    (Original post by betapro)
    Guys for the height question and volume for the first one, once you get 8 did you put units? I put 8 m^2 is that right, if not will ig et marked down?
    No because it was a rate without a time variable. meters cubed per meter is not meters^2, it doesn't quite work like that in real life from what I know.

    But maybe.
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    For the area question I left it as 6.25 - 14/3 rather than put 19/12 will I still get all the marks?
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    (Original post by Maligaha)
    Ehy are people gettibg k-1 im dead sure its 0.5k -0.5Name:  IMG_20160621_115223.jpg
Views: 203
Size:  474.5 KB
    You've subbed in the wrong value for X, it said from 1/2lnk
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    (Original post by Maligaha)
    It looks like you have....
    I know I didn't do that, I'd check over your maths as most people seem to have k-1 as the answer
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    (Original post by mrk1357)
    11*13=143

    143 is not divisible by 3

    so odd*odd=odd but isnt necessarily divisible by 3
    It had to be in the form 2^n-1, 2^n+1. 11 and 13 cannot be expressed in that form
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    How the hell did you do question 1? Integrating 1+cos1/2x or something.

    Is 1+cosx an identity?

    Posted from TSR Mobile
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    How did you solve the y intercept for e^2x+ke^(-2x)=0?
 
 
 
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