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# OCR MEI C3 Mathematics June 2016 - Official Thread watch

1. (Original post by Goulden_J)

It was all in the syllabus
If you wanted to be finnicky it technically is above the syllabus since the curve was 2cosh2x

But nah, it was tricky but not much variation in difficulty to the 2015 paper

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2. (Original post by Kira Yagami)
The lowest it's been is 51,54,55,56. It was 56 last year.

I think it should be 53/54 for an A , what do you think?
I've only looked at 90% boundaries before, but assuming 18/18 in coursework I'd guess 59 or 60 for 90 UMS in the exam.
3. I think minimum I got around 63 looking at my answers to the questions a bit more. Along with 18/18 on my coursework would that be a solid A?
4. Your teachers aren't properly qualified if they couldn't do any of it. I thought it was a tricky paper but definitely not too difficult. Expecting 53 for an A and 67 for full UMS.
5. I know I messed up and got the wrong answers for all of the last question And I had to get an A* - I guess that can't happen anymore
6. (Original post by OscarH98)
Your teachers aren't properly qualified if they couldn't do any of it. I thought it was a tricky paper but definitely not too difficult. Expecting 53 for an A and 67 for full UMS.
u mean 63
7. For the very last question I put that because g(X) is even that means the function is symmetrical about the y axis. Would I pick up any marks here?
8. (Original post by bethygirl)
I've seen posts on this thread saying the answer to the first part of the last question was k-1 however literally every body at my college got k+1?
its k-1, i plotted the function in my calculator with k as 7 and the area was 6. hence k-1
9. (Original post by Studious_Student)
I think minimum I got around 63 looking at my answers to the questions a bit more. Along with 18/18 on my coursework would that be a solid A?
Should be around 92-95 UMS in my opinion.
10. (Original post by mathsphys3)
For the very last question I put that because g(X) is even that means the function is symmetrical about the y axis. Would I pick up any marks here?
Yes. About y-axis or Oy is fine.
11. (Original post by mathsphys3)
For the very last question I put that because g(X) is even that means the function is symmetrical about the y axis. Would I pick up any marks here?
Maybe 1 as that was part of the reasoning for the line of symmetry for f(x).
12. (Original post by jakeshaw97)
its k-1, i plotted the function in my calculator with k as 7 and the area was 6. hence k-1
damn, you couldn't leave it as 2k-2?
13. (Original post by lollllll)
damn, you couldn't leave it as 2k-2?
2k-2 is not the same as k-1.
14. (Original post by lollllll)
damn, you couldn't leave it as 2k-2?
Well, you can't "simplify" 2k - 2 to k - 1. k - 1 was the correct answer. Always check your results on your calculator's integral button, even if it's in terms of a variable.
15. (Original post by lollllll)
damn, you couldn't leave it as 2k-2?
no, dont think that would work as 2*7-2=12 not 6. 2k-2 doesnt simplify to k-1, its just double it
16. This exam was definitely harder than last years - there is no doubting it.
There was lots of parts which would throw people back.
I expect grade boundaries to be 55-58.
17. I did question 5 with 4root(h^3 - 1) -4 do you reckon I'll get follow through marks cos obvs I got the wrong answer (:
18. (Original post by Leechayy)
If you wanted to be finnicky it technically is above the syllabus since the curve was 2cosh2x
and if you want to be finnickier it was actually 2sqrt(k)cosh2x ^^
19. (Original post by StrangeBanana)
and if you want to be finnickier it was actually 2sqrt(k)cosh2x ^^
That's the translated one isn't it?p

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20. for question 9.ii i showed that the minimum point has x co ordinate of 1/4ln4 and then i subbed that back into f(x) to find out the y co ordinate but i got an incorrect y co ordinate. how many marks in the question will i lose because of this

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