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    (Original post by Maliha01)
    Did people get 4 for the propotionality constant
    Think I got 1/4, not sure about it though. What did everyone get?
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    (Original post by HFancy1997)
    Some answers I got

    -Root10cos(theta+1.249)
    -Invalid because4/root10 is bigger than 1
    -P=2,Q=-2
    -Theta=90,26...?
    -volume=16Pie/3
    Area was 8
    -Q(12.5,6.5,2) not sure about y here
    Ratio 3:2?
    Last q was show thats
    and k=0.811?
    I agree with all but Q i got( 2.4, 1.6,2)
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    (Original post by slj997)
    Was it not 8pi/3 as it was only rotated through 180 degrees
    no, look at june 15. near exact same question. its because the shape was below the x axis too, so rotation was a full shape

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    (Original post by slj997;6606950k1)
    What did people get for the Cartesian equation of the plane and the angle between the plane and line AQ
    Can't remember the vector of the normal but was something like
    2x-Y+2Z -20 = 0

    Just depends the number of the normal vector for the values in front of X y and z
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    (Original post by slj997)
    Was it not 8pi/3 as it was only rotated through 180 degrees
    Nope, still the same.

    The graph was in 2 different quadrants, so rotating it 180 degrees gives the same volume as rotating the version of the graph with only 1 quadrant plotted, 360 degrees.
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    (Original post by Maliha01)
    I agree with all but Q i got( 2.4, 1.6,2)
    I got Q as this
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    (Original post by prepdream)
    Think I got 1/4, not sure about it though. What did everyone get?
    I also got 1/4, although I can't remember the question so can't check it.
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    (Original post by Maliha01)
    I agree with all but Q i got( 2.4, 1.6,2)
    Yeah I got this too, then ratio was 1:1.5 I think
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    Can anyone remember any answers to paper B?
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    (Original post by Maliha01)
    I agree with all but Q i got( 2.4, 1.6,2)
    Ah I meant 12/5 and yeah I remember now thanks!

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    That was ridiculously hard
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    (Original post by Maliha01)
    I agree with all but Q i got( 2.4, 1.6,2)
    I got the same for Q
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    (Original post by prepdream)
    Think I got 1/4, not sure about it though. What did everyone get?
    I got 1/4ln(2x+1/2x-l)= t and just thought that we had to multiply by four to get rid of the 1/4 im not entirely sure about it though.... i feel like im wrong
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    (Original post by Qwertykeyboard15)
    Can anyone remember any answers to paper B?
    11.35 for some angle and 104.5 for question 1
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    If someone can remind me of the questions somehow, I'll get a full unofficial mark scheme done
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    Some answers I got

    -Root10cos(theta+1.249)
    -Invalid because4/root10 is bigger than 1
    -P=2,Q=-2
    -Theta=90,26...?
    -volume=16Pie/3
    Area was 8
    -Q(12/5,8/5,2)
    Ratio 3:2? might be 2:3 cant remember which way
    Last q was show thats
    and k=0.811?

    Updated

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    (Original post by Qwertykeyboard15)
    Can't remember the vector of the normal but was something like
    2x-Y+2Z -20 = 0

    Just depends the number of the normal vector for the values in front of X y and z
    The equation was 15x-20y+4z= 20
    The angle was 56.04 i guess
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    Do you still get marks if you haven't simplified the ratio right down?
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    That was so hard.
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    can somebody confirm theta is 26? im not 100percent sure

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