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    It's basically when the acceleration of the plate when it moves downwards is faster than free falls (9.81ms-2) so when the plate moves down faster than the particles ontop can fall then they will lose contact for a brief time
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    Make sure you remember the Joules->W->KWh conversions. I didnt find it in the textbook in this unit but it shows up in the papers
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    do we need to know : change in energy= mass* specific latent heat
    ive never seen it come up
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    Anyone know what experiments could possibly come up in the paper?
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    Anyone got the 2015 past paper?
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    (Original post by Stahri)
    Anyone know what experiments could possibly come up in the paper?
    I think the specific heat capacity is coming up. It's on the 2014 June paper if you want to know it.
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    Mass of S2 - go!
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    That was not bad for me apart from that ****ING alphabet question, pisses me off! I almost lost all those marks. But that was not a normal paper, although they were all answerable but literally NO easy questions, even defining internal energy was hard.

    For the energy of the pellets, did you guys do mgh * 50? or what did you do to get the E for the specific heat capacity.

    And for the forces similarity I said,
    - Same magnitude, same type of force
    - Opposite direction, does not act on the same object.

    Who agrees??

    For the Kepler's law question, I did T2/r3 = T2/r3, right?

    For the first question for the first part where you had to get speed. I did I = Ft, and then I = change in momentum to get speed. For the next part I used SUVAT, but last part of that question, finding the height I could not do, I tried but got 7m which is the initial height, and it can't be that.

    Let me know what you guys did, and what you did for those questions.
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    (Original post by Reda2)
    That was not bad for me apart from that ****ING alphabet question, pisses me off! I almost lost all those marks. But that was not a normal paper, although they were all answerable but literally NO easy questions, even defining internal energy was hard.

    For the energy of the pellets, did you guys do mgh * 50? or what did you do to get the E for the specific heat capacity.

    And for the forces similarity I said,
    - Same magnitude, same type of force
    - Opposite direction, does not act on the same object.

    Who agrees??

    For the Kepler's law question, I did T2/r3 = T2/r3, right?
    All correct
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    (Original post by Reda2)
    ...
    yes for kepler's law you do that..
    specific heat capacity you times 1.2 by 50 and find gpe
    then use formula to find c
    messed up last question so bad though
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    For the first question for the first part where you had to get speed. I did I = Ft, and then I = change in momentum to get speed. For the next part I used SUVAT, but last part of that question, finding the height I could not do, I tried but got 7m which is the initial height, and it can't be that.

    Anyone?
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    (Original post by anonymous_veg)
    Mass of S2 - go!
    Something x10^33??
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    (Original post by cookie_raider01)
    yes for kepler's law you do that..
    specific heat capacity you times 1.2 by 50 and find gpe
    then use formula to find c
    messed up last question so bad though
    1.2 was the height right?
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    Very heavy on the maths this year. All in all a very fair and nice paper. Nothing too crazy IMO. The impulse question (at least I hope it was an impulse question!) threw me a little.
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    (Original post by cookie_raider01)
    yes for kepler's law you do that..
    specific heat capacity you times 1.2 by 50 and find gpe
    then use formula to find c
    messed up last question so bad though
    I was doing the last question as the time ended, I got to the part where I'm putting the values in the calculator. Due to not having time, I wrote R instead of the actual value, do you think that will cost me the mark?
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    (Original post by AlexeiLipov)
    Something x10^33??
    How did you do that question?
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    How did people do the KE graph? Was your max KE at 50? And start from 0?
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    (Original post by Reda2)
    How did you do that question?
    Not sure if it's right but I used Kepler's third law equation, we know time period, and radius (found out in previous part) so we can find out the mass.
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    About same difficulty as last year maybe a little easier. So
    52 - 90 UMS
    48 - A*
    44 - A
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    wasn't the graph like this???
 
 
 
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