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    (Original post by Pink1998)
    Hi, for last year's June 2015 paper. In the last question they've written P(X>w / X>28)
    Is that "/" a divide sign or a "given that" sign?
    Thank you
    given that.
    same applies to standard probability qs
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    (Original post by jackf9283)
    if you have boundaries of 0-4 is the class width of that data 4.5 or 5 as the upper bound would be 4.5 assuming the next boundary if 5-something. But would you use -0.5 or just 0
    Im guessing it would be 0, depends on the context of the question for example you cant drive negative 0.5 miles something like that hope it helps
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    (Original post by MMMSS)
    were you able to find the regression line in terms of and b?
    y=0.746+0.102x
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    Using a venn diagram..

    ...how would you work out P(A' U B) and P(A' U B')?? ? ?

    Thanks!!
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    (Original post by AlphaWolfZ)
    Mega Thanks buddy. Why do you divide one over the other? Is that the rule?
    The rule is P(B|A) = P(AnB)/P(A) so it's the probability of both events divided by the given event. For example in the phone charger question, for both events to occur it has to be greater than 133. Do you see what I mean?
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    (Original post by Guèpard)
    ExamSolutions is playing up!

    Seriously, now had to be the time
    yh so tru i thought it was my internet connection being slow
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    (Original post by Guèpard)
    ExamSolutions is playing up!

    Seriously, now had to be the time
    Normally happens the night before an exam, the website gets a lot of traffic.
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    (Original post by Jack_Linaker)
    The rule is P(B|A) = P(AnB)/P(A) so it's the probability of both events divided by the given event. For example in the phone charger question, for both events to occur it has to be greater than 133. Do you see what I mean?
    Slightly. How do we work out P(AnB)?
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    (Original post by SweetChilliCake)
    y=0.746+0.102x
    Ok so it's a matter of substitution- youve been given the codes for x and y

    so instead of y=0.746+0.102x,
    you will now get v/100,000 = 0.746 + 0.102*(s-50/10)

    then simplify:
    v= 23600 + 1020 s

    ergo, d= 1020
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    (Original post by AlphaWolfZ)
    Slightly. How do we work out P(AnB)?
    That's the probability of both events occurring, A and B. In the case of the phone charger question you work it out the same way you worked out P(L>127) in part a.
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    does anyone know the grade boundaries for the 2016 IAL S1 paper?
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    When you draw a regression line, does it go through the mean point?
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    (Original post by siamesedaffodil)
    Using a venn diagram..

    ...how would you work out P(A' U B) and P(A' U B'?? ? ?

    Thanks!!
    P(A'UB) would be everything except P(A)-P(AnB) so just everything but the bit where A doesnt overlap with B including the outside area.
    P(A'UB') would be the outside area
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    (Original post by studentsixth)
    When you draw a regression line, does it go through the mean point?
    Yes it should
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    This only means that it is not A and is B which means that it is all the probabilities that cover that area
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    (Original post by studentsixth)
    When you draw a regression line, does it go through the mean point?
    I'm pretty sure, yeah.
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    how you all feeling for tomorrow?/
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    (Original post by Exavior)
    P(A'UB) would be everything except P(A)-P(AnB) so just everything but the bit where A doesnt overlap with B including the outside area.
    P(A'UB' would be the outside area
    P(A'UB') is everything apart from P(A intersection B)
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    For normal distribution is the middle line/axis the mean? So its usually 0 but for Z it would be the mean??
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    (Original post by HK4)
    For normal distribution is the middle line/axis the mean? So its usually 0 but for Z it would be the mean??
    Yes, where the bell shaped curve peaks is the mean for ANY normal distribution.

    When in 'Z' the mean is 0 yes
 
 
 
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