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    0.5cm^2 was the area that represented 1 person.
    since the class had 17 people, we can find the area by multiplying 0.5 by 17, which equalled 8.5cm^2
    and the width for that question was 0.5cm
    therefore, to find height we divide 8.5 by 0.5, which equalled 17
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    i got 40 something people to eat dinner what about everyone else?
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    (Original post by WashingPowder)
    1. 9.44 , y= 0.722 + 0.0142x (Not with y and x , but w/e they gave you) , 5.692 ,
    2 or 3. 0.15 , 0.175 , 0.65, -0.754?
    4. 0.03 (Probability of D but nothing else?), 0.22 (Just Room no dinner/breakfast), 0.45 (The p(D | B overlap R)), 0.405 (p(D | B overlap R' )), 33 (No of Dinners? or w/e it was)
    5. 17cm (height) , 3.39 (Median) , 3.43 (mean), 0.68 (Standard Deviation), 0.2546 (The probability).
    6. 0.0668 (Probability of W > 240??) , 206.33m (Minimum distance Nathaniel had to run to be in top 20%) , 0.82 , 0.36 (The P ( z < mu - 40 | z< mu)) or w/e it was

    Theres my answers, See if you got any the same
    How did you work out the number of diners?
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    (Original post by mbh16)
    i got 40 something people to eat dinner what about everyone else?
    I dont hink anyone got coherent answers on this one lol
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    (Original post by WashingPowder)
    1. 9.44 , y= 0.722 + 0.0142x (Not with y and x , but w/e they gave you) , 5.692 ,
    2 or 3. 0.15 , 0.175 , 0.65, -0.754?
    4. 0.03 (Probability of D but nothing else?), 0.22 (Just Room no dinner/breakfast), 0.45 (The p(D | B overlap R)), 0.405 (p(D | B overlap R' )), 33 (No of Dinners? or w/e it was)
    5. 17cm (height) , 3.39 (Median) , 3.43 (mean), 0.68 (Standard Deviation), 0.2546 (The probability).
    6. 0.0668 (Probability of W > 240??) , 206.33m (Minimum distance Nathaniel had to run to be in top 20%) , 0.82 , 0.36 (The P ( z < mu - 40 | z< mu)) or w/e it was

    Theres my answers, See if you got any the same
    i remember the median to be 3.47
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    (Original post by kelvin1745)
    0.5cm^2 was the area that represented 1 person.
    since the class had 17 people, we can find the area by multiplying 0.5 by 17, which equalled 8.5cm^2
    and the width for that question was 0.5cm
    therefore, to find height we divide 8.5 by 0.5, which equalled 17
    oh nice i got this too
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    (Original post by wr123)
    I'm thinking more along the lines of 58/75 for an A
    Last year's was harder tho?
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    (Original post by Avocado2002)
    How did you work out the number of diners?
    expected =probability x number

    you times the probabilities you got in the previous ones by the numbers they gave you and add them.

    its the same thing as E(x)
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    The answer for the dinner q was 33!
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    (Original post by alexesl17)
    i remember the median to be 3.47
    i do too
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    (Original post by mbh16)
    i got 40 something people to eat dinner what about everyone else?
    i got 33
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    (Original post by Apolexian)
    expected =probability x number

    you times the probabilities you got in the previous ones by the numbers they gave you and add them.

    its the same thing as E(x)
    I did this and I got 33 Lol
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    (Original post by Avocado2002)
    What was the WJEC S1 exam like?
    Personally i found it pretty difficult but in general the people i have talked to have had a better time but unfortunately as i said earlier hardly anyone does WJEC
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    For question 2, I got Var(X) = 2.115.
    For question 6, I got 4 hours 34 minutes (or 274 mins).

    (Original post by Florent venhari)
    For question 6.a, i left it as the probability. Will i lose a mark for not multiplying by 100?
    Absolutely not. You can never just randomly multiply anything by 100 - you could have multiplied by 100% (which is equal to one) - but the question did not specify to leave your answer as a percentage so any form (decimal, fraction, percentage, heck even a per mille) should be fine.
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    (Original post by Siddhart1998)
    Last year's was harder tho?
    true im thinking 60 for an A
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    [QUOTE=Florent venhari;65797623]For question 6.a, i left it as the probability. Will i lose a mark for not multiplying by 100?
    No i have seen on previous mark schemes they will allow it
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    wheres the unofficial mark scheme at for edexcel s1.........
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    did anyone get 0 for one of the probability questions?
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    Its very similar to this question from the June 2014(AIL) which luckily i did last night. But you basically , for the question above you would do 27 * P(D | M n S) + 36 * P(D | M n S') to find the total that had desserts
    (Original post by Avocado2002)
    How did you work out the number of diners?
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    (Original post by mbh16)
    i got 40 something people to eat dinner what about everyone else?
    yeah I got like 47
 
 
 
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