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OCR Chemistry A Exam Thread (Breadth - May 27 2016 and Depth - June 10 2016) watch

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    Highly unlikely but if everyone does terrible then its possible
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    (Original post by olloloplplpollp)
    would u say 30-34 is a C
    It could be but just focus on doing well in the exam so you don't have to worry about the grade boundaries for a C

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    (Original post by alfmeister)
    It could be but just focus on doing well in the exam so you don't have to worry about the grade boundaries for a C

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    what topics should i focus a lot on?
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    (Original post by olloloplplpollp)
    what topics should i focus a lot on?
    If I was you I would just start to do as many papers as you can by tomorrow.
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    Personally i'm focussing a lot on the mathsy stuff because that's what came up a lot in the specimen, less so about the tests side because the paper 2 specimen was more test heavy with 5 and 6 markers in it. Generally everything though. Really hoping not to fail my track record is awful so far and i'm hoping to really turn it around for the big one!
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    (Original post by olloloplplpollp)
    what topics should i focus a lot on?
    I personally feel that you should feel very comfortable with moles and all the calculation that entices such ideal gas equation, calculating concentration etc. and also all of the reaction mechanisms. However you should revise the material which you are not confident with.
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    Am proper bricking it liark. Anyone got any pointers?
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    Did bio today. So much easier than specimen. We gonna be okay


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    (Original post by Clintbarton)
    Did bio today. So much easier than specimen. We gonna be okay


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    That's what I was thinking
    Hope so, anyway!!
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    (Original post by torilee)
    That's what I was thinking
    Hope so, anyway!!
    Was it ocr or aqa?
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    (Original post by Saaranjan)
    Was it ocr or aqa?
    OCR
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    (Original post by torilee)
    OCR
    This news has made me very happy ahahhahaha
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    Yeah bio today was easier than the specimen. Heard the same for physics so hopefully it will be 3/3 with chem
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    (Original post by 4nonymous)
    Yeah bio today was easier than the specimen. Heard the same for physics so hopefully it will be 3/3 with chem
    Was the bio exam you did today the same difficulty as past papers from previous years?
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    All nighter for me tonight... Didnt do any chemistry after 3 days of physics, maths and biology.
    Hopefully it'll be alright.
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    (Original post by Saaranjan)
    Was the bio exam you did today the same difficulty as past papers from previous years?
    Yes, although sometimes the MCQ can trick you sometimes but other than that I'd expect quite high grade boundaries if chem is the same difficulty as the biology
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    (Original post by 4nonymous)
    Yes, although sometimes the MCQ can trick you sometimes but other than that I'd expect quite high grade boundaries if chem is the same difficulty as the biology
    Biology was soo easy but people are saying it was difficult? Like ???? There were so many straightforward answers.


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    (Original post by Clintbarton)
    Biology was soo easy but people are saying it was difficult? Like ???? There were so many straightforward answers.


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    Yes quite a lot of people found it easy. I found it ok I messed up a few but Im not that bothered. I expect there to be high grade boundaries for it to be honest.
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    Colourless solutions of X(aq) and Y(aq) react to form an orange solution of Z(aq)according to the following equation. X(aq) + 2Y(aq) Z(aq) ∆H=–20kJmol–1 A student added a solution containing 0.50 mol of X(aq) to a solution containing0.50 mol of Y(aq) and shook the mixture.
    After 30 seconds, there was no further change in colour.
    The amount of Z(aq) at equilibrium was 0.20 mol. [2 marks] Deduce the amounts of X(aq) and Y(aq) at equilibrium. How do you do this?
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    (Original post by Saaranjan)
    Colourless solutions of X(aq) and Y(aq) react to form an orange solution of Z(aq)according to the following equation. X(aq) + 2Y(aq) Z(aq) ∆H=–20kJmol–1 A student added a solution containing 0.50 mol of X(aq) to a solution containing0.50 mol of Y(aq) and shook the mixture.
    After 30 seconds, there was no further change in colour.
    The amount of Z(aq) at equilibrium was 0.20 mol. [2 marks] Deduce the amounts of X(aq) and Y(aq) at equilibrium. How do you do this?
    So you know there is 0.5 of X and Y and at the start there is 0 moles of Z
    At equilibrium Z=0.2 moles
    So that means X=0.5-0.2
    And Y=0.5-(2*0.2) because Y is two moles so times by 2
 
 
 
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