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imasillynarb

What did you get for P? What did you get for the angle for the impulse question and the angle for the centre of mass question?

0.4mg < P < 13.6mg

The angle for the impulse question was somewhere around 60-80, and the angle for the CM question was somewhere between 15-25. I don't really remember.

Ermmm... P is between 1.95mg and 6.3mg....

I'm certainly wrong on that one then!!!

Anyway, ce la vis!

I did well enough on the rest of it!

I'm certainly wrong on that one then!!!

Anyway, ce la vis!

I did well enough on the rest of it!

Impulse question was quite easy to make a mistake on I reckon..

P = 0.4mg, I got that as well, except theyre not going to give you 7 marks for rearraging F + P = N

So that ones wrong.

As with the impulse question, it wanted the angle of projection. The balls comes in at 30i and is projected at root(5^2 + 25^2???), so you wanted the angle between the resultant and the 30i, not the angle between 5 and 25, I think

P = 0.4mg, I got that as well, except theyre not going to give you 7 marks for rearraging F + P = N

So that ones wrong.

As with the impulse question, it wanted the angle of projection. The balls comes in at 30i and is projected at root(5^2 + 25^2???), so you wanted the angle between the resultant and the 30i, not the angle between 5 and 25, I think

imasillynarb

Err, why do you assume 2 cases? You know which way the friction acts. Its not a 'maybe' ...

Friction acts opposite to motion. In the default case, it acts opposite to the motion of the ladder, i.e. to the right. However, when P becomes strong enough to break equilibrium, friction acts opposite to it, i.e. to the left.

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