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# Edexcel M2 watch

1. (Original post by 786)
The ball was travelling initially along the x-axis, and ended up in a direction arctan 2 below, thus it was deflected through arctan 2 degrees.
=63.4 degrees, i agree.
2. (Original post by Indelible)
=63.4 degrees, i agree.

yessssssssss that was the best paper of all the exams i hav given in JUNE
3. did u guys get 48m for the distance the skier travelled after leaving the slope, and hitting the ground with speed 23.6 m/s??
4. (Original post by olliemccowan)
did u guys get 48m for the distance the skier travelled after leaving the slope, and hitting the ground with speed 23.6 m/s??
yep, didnt like that though, 48m seemed ridiculously far, no air resistance though I suppose
5. how about (2t² - 7t + 3)i + (5 - 5t)j for the position vector, with a collision occuring at t=2.5 seconds?
6. (Original post by olliemccowan)
did u guys get 48m for the distance the skier travelled after leaving the slope, and hitting the ground with speed 23.6 m/s??
7. (Original post by olliemccowan)
how about (2t² - 7t + 3)i + (5 - 5t)j for the position vector, with a collision occuring at t=2.5 seconds?

yup got it that right too
8. and how about a rate of work of 44.4 kW for 1(b) and an energy loss of 40J for 2(c)?
9. (Original post by olliemccowan)
and how about a rate of work of 44.4 kW for 1(b) and an energy loss of 40J for 2(c)?
score again mate
10. yes! i got every question rite, like i dun for S2 - he he now i can completely bugger up P4 and P6 lol. cheers guys
11. (Original post by olliemccowan)
yes! i got every question rite, like i dun for S2 - he he now i can completely bugger up P4 and P6 lol. cheers guys
Lol so similar to how I felt: "great, I got a good mark there, maybe that will cancel out my P3 grade!"
12. (Original post by XYTER)
I've got the paper here and it says the angle at which the ball is DEFLECTED as a result of the impact

Any chance you could put the paper up on the site? I'm sure everyone would be very grateful.

Edit ooh ps: how many marks was the 'find range of values of p' worth for definite then?
13. So many people have posted answers, I'm going to go through and agree with the following:

In Q1 I got a=0.7m/s^2 and a work rate of 44,400W.
I got the COM as 5/6cm from BC. I don't think it asked for a horizontal distance.
As I confirmed earlier, I got 63.4 degrees on the impulse question.
On Q8 I eventually got t = 3. That's after I did -8 = 12t **+** 4.9t^2.
I had a 23.6m/s impact speed and a horizontal distance of 16t = 48m.
(2t² - 7t + 3)i + (5 - 5t)j and t=(5/2)s ring a bell for one question.

As I mentioned earlier, I can upload my written answers to any question if anyone can post the question. I tend to find it easier to look at written answers for comparison instead of compu-type, all these ^2's etc.
14. (Original post by sam99)
Any chance you could put the paper up on the site? I'm sure everyone would be very grateful.

Edit ooh ps: how many marks was the 'find range of values of p' worth for definite then?
Definately 7 marks. I remember worrying about it.
15. (Original post by SRKeates)
Definately 7 marks. I remember worrying about it.
great. THere goes my 90%
16. (Original post by sam99)
great. There goes my 90%
Not quite. Assuming you get 100% on the rest of the paper, you'll still get 90.6% overall. If you mean 90 UMS marks, depending on the grade boundary, it's quite possible to get 90.
17. (Original post by sam99)

Edit ooh ps: how many marks was the 'find range of values of p' worth for definite then?
7 99% sure
18. (Original post by olliemccowan)
how about (2t² - 7t + 3)i + (5 - 5t)j for the position vector, with a collision occuring at t=2.5 seconds?
hey then the veloc of it was 2t-7? because i read 4t-7 and got 4t^2-7t + blabla and my coeff was screwed, though i got 2.5secs for coeff of j
hey then the veloc of it was 2t-7? because i read 4t-7 and got 4t^2-7t + blabla and my coeff was screwed, though i got 2.5secs for coeff of j
The velocity of it was 4t - 7, which integrates to form 2t^2 - 7t.
20. (Original post by SRKeates)
The velocity of it was 4t - 7, which integrates to form 2t^2 - 7t.
+C lol, sorry

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