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    (Original post by 786)
    The ball was travelling initially along the x-axis, and ended up in a direction arctan 2 below, thus it was deflected through arctan 2 degrees.
    =63.4 degrees, i agree.
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    (Original post by Indelible)
    =63.4 degrees, i agree.

    yessssssssss that was the best paper of all the exams i hav given in JUNE
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    did u guys get 48m for the distance the skier travelled after leaving the slope, and hitting the ground with speed 23.6 m/s??
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    (Original post by olliemccowan)
    did u guys get 48m for the distance the skier travelled after leaving the slope, and hitting the ground with speed 23.6 m/s??
    yep, didnt like that though, 48m seemed ridiculously far, no air resistance though I suppose
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    how about (2t² - 7t + 3)i + (5 - 5t)j for the position vector, with a collision occuring at t=2.5 seconds?
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    (Original post by olliemccowan)
    did u guys get 48m for the distance the skier travelled after leaving the slope, and hitting the ground with speed 23.6 m/s??
    yes thats the answer
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    (Original post by olliemccowan)
    how about (2t² - 7t + 3)i + (5 - 5t)j for the position vector, with a collision occuring at t=2.5 seconds?

    yup got it that right too
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    and how about a rate of work of 44.4 kW for 1(b) and an energy loss of 40J for 2(c)?
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    (Original post by olliemccowan)
    and how about a rate of work of 44.4 kW for 1(b) and an energy loss of 40J for 2(c)?
    score again mate
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    yes! i got every question rite, like i dun for S2 - he he now i can completely bugger up P4 and P6 lol. cheers guys
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    (Original post by olliemccowan)
    yes! i got every question rite, like i dun for S2 - he he now i can completely bugger up P4 and P6 lol. cheers guys
    Lol so similar to how I felt: "great, I got a good mark there, maybe that will cancel out my P3 grade!"
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    (Original post by XYTER)
    I've got the paper here and it says the angle at which the ball is DEFLECTED as a result of the impact

    Any chance you could put the paper up on the site? I'm sure everyone would be very grateful.


    Edit ooh ps: how many marks was the 'find range of values of p' worth for definite then?
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    So many people have posted answers, I'm going to go through and agree with the following:

    In Q1 I got a=0.7m/s^2 and a work rate of 44,400W.
    I got the COM as 5/6cm from BC. I don't think it asked for a horizontal distance.
    As I confirmed earlier, I got 63.4 degrees on the impulse question.
    On Q8 I eventually got t = 3. That's after I did -8 = 12t **+** 4.9t^2.
    I had a 23.6m/s impact speed and a horizontal distance of 16t = 48m.
    (2t² - 7t + 3)i + (5 - 5t)j and t=(5/2)s ring a bell for one question.

    As I mentioned earlier, I can upload my written answers to any question if anyone can post the question. I tend to find it easier to look at written answers for comparison instead of compu-type, all these ^2's etc.
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    (Original post by sam99)
    Any chance you could put the paper up on the site? I'm sure everyone would be very grateful.


    Edit ooh ps: how many marks was the 'find range of values of p' worth for definite then?
    Definately 7 marks. I remember worrying about it.
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    (Original post by SRKeates)
    Definately 7 marks. I remember worrying about it.
    great. THere goes my 90% :mad:
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    (Original post by sam99)
    great. There goes my 90% :mad:
    Not quite. Assuming you get 100% on the rest of the paper, you'll still get 90.6% overall. If you mean 90 UMS marks, depending on the grade boundary, it's quite possible to get 90.
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    (Original post by sam99)

    Edit ooh ps: how many marks was the 'find range of values of p' worth for definite then?
    7 99% sure
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    (Original post by olliemccowan)
    how about (2t² - 7t + 3)i + (5 - 5t)j for the position vector, with a collision occuring at t=2.5 seconds?
    hey then the veloc of it was 2t-7? because i read 4t-7 and got 4t^2-7t + blabla and my coeff was screwed, though i got 2.5secs for coeff of j
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    (Original post by BossLady)
    hey then the veloc of it was 2t-7? because i read 4t-7 and got 4t^2-7t + blabla and my coeff was screwed, though i got 2.5secs for coeff of j
    The velocity of it was 4t - 7, which integrates to form 2t^2 - 7t.
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    (Original post by SRKeates)
    The velocity of it was 4t - 7, which integrates to form 2t^2 - 7t.
    +C lol, sorry
 
 
 
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