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    (Original post by Indelible)
    +C lol, sorry
    I was using magic limits! I forgot to mention the upper limit of t and the lower limit of 0, which as you know ( ) was part of the question!
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    (Original post by SRKeates)
    The velocity of it was 4t - 7, which integrates to form 2t^2 - 7t.
    ohhh u were meant to integrate it! i wondered why i didnt remember integrating at the end!lol oopsie :rolleyes:
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    (Original post by SRKeates)
    I was using magic limits! I forgot to mention the upper limit of t and the lower limit of 0, which as you know ( ) was part of the question!
    ohhhhhh you gota love them magic limits!
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    1) 0.7 ms^-2
    b) 44.4kW

    2a) 10i + 20j
    2b) angle = 116.6 (i think this should be 180-116.6=63.4)
    c) 40J

    3) 5/6 cm above
    b) 14.6

    4= too long to write
    b) yes at 5/2

    5c) f>1/9
    6b) 2mg/5<p<13 3/5 mg

    7) 52N
    b) t=3
    c) 48m
    d) 23.6 ms
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    (Original post by matouwah)
    1) 0.7 ms^-2
    b) 44.4kW

    2a) 10i + 20j...

    ...c) 48m
    d) 23.6 ms
    I'm recognising all of them, apart from 6 b) which I know I made mistakes on. And I would agree that the 63.4 degree angle is more realistic. It all depends on how you set up the physical/mental triangle.
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    i agree completely wiv them answers
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    yeah i drew a diagram and got an obtuse angle and an acute angle....i think the angle of deflection was asked...but i guess i will lose one mark there.....coz my diagram was big ...
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    (Original post by shift3)
    Everyone I spoke to got a=0.7, but I got 1.2, and I can't see where I went wrong.

    Can anyone please clarify?
    I think you've failed to take into the account the resistance to motion (I think it was specified). As:

    36000/20 - R = 1500a

    If you discount R, a=1.2m/s^2.
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    (Original post by matouwah)
    yeah i drew a diagram and got an obtuse angle and an acute angle....i think the angle of deflection was asked...but i guess i will lose one mark there.....coz my diagram was big ...
    This is exactly what I did:

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    someone must have taken a copy of the paper once they'd finished...cmon i wanna calculate how much i got!
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    (Original post by BossLady)
    someone must have taken a copy of the paper once they'd finished...cmon i wanna calculate how much i got!
    I live only a short walk from my college. I'm tempted to go back and ask my Maths lecturer for a copy. I'd get it another day, but that M2 exam was the last time I'll step foot in my college until results day.
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    (Original post by matouwah)
    1) 0.7 ms^-2
    b) 44.4kW

    2a) 10i + 20j
    2b) angle = 116.6 (i think this should be 180-116.6=63.4)
    c) 40J

    3) 5/6 cm above
    b) 14.6

    4= too long to write
    b) yes at 5/2

    5c) f>1/9
    6b) 2mg/5<p<13 3/5 mg

    7) 52N
    b) t=3
    c) 48m
    d) 23.6 ms

    ahhh that looks useful.....you remember the marks?
    I filled in what i remember

    1) 0.7 ms^-2
    b) 44.4kW

    2a) 10i + 20j
    2b) angle = 116.6 (i think this should be 180-116.6=63.4)
    c) 40J

    3) 5/6 cm above
    b) 14.6

    4= too long to write (5)
    b) yes at 5/2 (7)

    5
    a) (5?)
    b) (3)
    c) f>1/9 (3)
    6b) 2mg/5<p<13 3/5 mg (7)

    7) 52N
    b) t=3
    c) 48m
    d) 23.6 ms
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    (Original post by SRKeates)
    I live only a short walk from my college. I'm tempted to go back and ask my Maths lecturer for a copy. I'd get it another day, but that M2 exam was the last time I'll step foot in my college until results day.
    was that your last exam?
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    how much was the angle question.....

    how many marks would i lose if i had a clear diagram and worked out the acute angle however did 180-that and gave the obtuse angle as my final answer?
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    [QUOTE=BossLady]ahhh that looks useful.....you remember the marks?
    I filled in what i remember


    nope...hahah thought it wouldnt matter coz all of my answers were rite...turns out i was wrong...lol
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    (Original post by BossLady)
    was that your last exam?
    Yes, it was.

    And to matouwah, a little mistake like that in a mega-marks M2 question, I believe, is only going to cost you 1 to 2 marks at the absolute most.
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    How many marks was 1.b) worth?
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    (Original post by JaF)
    How many marks was 1.b) worth?
    Four seems to spring to mind.
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    did the com questions specifically ask for distance from AB? coz i got my answer to be 3,5,6 because i did it from the bottom?
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    (Original post by Hovick)
    did the com questions specifically ask for distance from AB? coz i got my answer to be 3,5,6 because i did it from the bottom?
    It specifically asked for the distance of the COM from BC, which was the horizontal line that acted as the bottom of the "tree". Considering that the box was 3cm in height, you have calculated it to be 5/6cm from BC. As long as you didn't write expressly that the COM is 3+(5/6)cm from BC or anything else, you should be fine.
 
 
 
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