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    https://gyazo.com/b6a487a53f8a1bbcae1691b914e10743

    https://gyazo.com/0134cfc3753f35759bda02e7a652b643

    https://gyazo.com/674eb43a91648fe2850b342702ba8af8

    I'm having trouble understanding the Nth term and how it works..

    Could someone please explain?
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    It is just the general term of a sequence. By which I mean you can substitute any of the numbers 1,2,3, ... for n and get that term. It's actually a lot more simple than it may seem at first.
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    (Original post by KyleH123)
    https://gyazo.com/b6a487a53f8a1bbcae1691b914e10743

    https://gyazo.com/0134cfc3753f35759bda02e7a652b643

    https://gyazo.com/674eb43a91648fe2850b342702ba8af8

    I'm having trouble understanding the Nth term and how it works..

    Could someone please explain?
    I understand that the sequence goes up a certain amount every time, but I don't understand the rest
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    (Original post by A Slice of Pi)
    It is just the general term of a sequence. By which I mean you can substitute any of the numbers 1,2,3, ... for n and get that term. It's actually a lot more simple than it may seem at first.
    hey, thanks for replying, would you be up for going through some higher papers on skype?
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    The formula is the difference + (the first term - the difference)

    11,15,19,23

    The difference is 4 so its 4n + (11-4) so 4n + 7

    4x1 + 7 = 11 / 4x2 + 7 =15 / 4x3 + 7 = 19 etc..
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    (Original post by JamesN88)
    The formula is the difference + (the first term - the difference)

    11,15,19,23

    The difference is 4 so its 4n + (11-4) so 4n + 7

    4x1 + 7 = 11 / 4x2 + 7 =15 / 4x3 + 7 = 19 etc..
    (That only works for linear sequences)
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    (Original post by JamesN88)
    The formula is the difference + (the first term - the difference)

    11,15,19,23

    The difference is 4 so its 4n + (11-4) so 4n + 7

    4x1 + 7 = 11 / 4x2 + 7 =15 / 4x3 + 7 = 19 etc..
    i don't understand why i'm finding this so difficult..
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    could someone skype with me and explain? :s
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    The sequences that you cover at GCSE are called 'arithmetic', and they change by the same amount each time. The nth term of a sequence like this is usually written as a + (n-1)d, where "a" represents the first term, and "d" the amount by which the terms change each time. So for example, in the sequence 2, 4, 6, 8, 10, ... the first term "a" is 2, and the amount by which the terms change "d" is also 2. So the nth term is 2 + 2(n-1) = 2n (when you expand the brackets and simplify). It also works when the terms are decreasing. For example in 1, -3, - 7, -11, -15 ... the first term a = 1 and the difference between the terms is -4 (because they are decreasing). Putting these into the formula gives the nth term as 1 - 4(n-1) = 5 - 4n.
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    (Original post by KyleH123)
    hey, thanks for replying, would you be up for going through some higher papers on skype?
    Sorry but I don't have skype
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    why don't you use youtube and watch videos on nth terms!
    there are tonnes of videos
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    (Original post by fatima1998)
    why don't you use youtube and watch videos on nth terms!
    there are tonnes of videos
    i'll try that!
 
 
 
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