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# M1 vector watch

1. for a) why is the angle not 56.3 but instead 90+56? I thought this is the angle we are looking for Attachment 511575511577 and for b) why isn't it just (2i-3j)t? In the mark scheme acceleration is included as well but how could that fit into the equation?? Thank you.
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2. (Original post by coconut64)
for a) why is the angle not 56.3 but instead 90+56? I thought this is the angle we are looking for Attachment 511575511577 and for b) why isn't it just (2i-3j)t? In the mark scheme acceleration is included as well but how could that fit into the equation?? Thank you.
The angle you've found is the angle between and the direction of motion, not the angle requested.
As for part b) think suvat:
Spoiler:
Show
So .
3. (Original post by joostan)
The angle you've found is the angle between and the direction of motion, not the angle requested.
As for part b) think suvat:
Spoiler:
Show
So .
Oh I get it. For your equation is that the v=u+at equation? Is v0 u? Cheers.
4. (Original post by coconut64)
Oh I get it. For your equation is that the v=u+at equation? Is v0 u? Cheers.
Yes, is an initial velocity.
5. (Original post by joostan)
Yes, is an initial velocity.
Now this makes sense. So this euqation is used when you only know the intial v and a ?
6. (Original post by coconut64)
Now this makes sense. So this euqation is used when you only know the intial v and a ?
This is equivalent to component-wise suvat and applies for constant acceleration.
You can use this exactly as you used the single dimensional equivalent .

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