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# A2 chemistry f325 Buffer question HELP!! watch

1. Stuck on this confusing buffer question! Q4eiii) from the f325(EEE) June 15 paper. Student adds 6.075g Mg to 1.00dm^3 of the buffer solution, calculate new Ph of buffer?. Previous info: Buffer solution contatins propanoic acid, C2H5COOH and propanoate ions. The concentrations are both 1.00 mol dm-3. Ka for C2H5COOH is 1.35*10^-3. ANY HELP WOULD BE APPRECIATED!
2. (Original post by Ss0)
Stuck on this confusing buffer question! Q4eiii) from the f325(EEE) June 15 paper. Student adds 6.075g Mg to 1.00dm^3 of the buffer solution, calculate new Ph of buffer?. Previous info: Buffer solution contatins propanoic acid, C2H5COOH and propanoate ions. The concentrations are both 1.00 mol dm-3. Ka for C2H5COOH is 1.35*10^-3. ANY HELP WOULD BE APPRECIATED!
pH = pKa + log([salt]/[acid])

So, find the concs and get the pKa from Ka (using -log_10).
The salt is Mg(C2H5O)2. Find its conc. Consider the reaction equation for ratios.

Hopefully, that's a start.
3. This paper is still secure, i.e. it should not be available to the public.

It really shouldn't be discussed.
4. Oh thankyou, i'll try this method.
5. (Original post by Ss0)
Stuck on this confusing buffer question! Q4eiii) from the f325(EEE) June 15 paper. Student adds 6.075g Mg to 1.00dm^3 of the buffer solution, calculate new Ph of buffer?. Previous info: Buffer solution contatins propanoic acid, C2H5COOH and propanoate ions. The concentrations are both 1.00 mol dm-3. Ka for C2H5COOH is 1.35*10^-3. ANY HELP WOULD BE APPRECIATED!
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