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Size:  144.3 KBCould someone prove 2B pls


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    (Original post by Dr Cobbold)
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    Integrate the function, use the given point to find the constant, then find the coordinates of A.
    Now use f ' (x) to find the gradient of the tangent. The negative reciprocal is the gradient of the normal!
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    (Original post by Dr Cobbold)
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    the normal to the curve has a gradient which is a negative reciprocal to the tangent. so if we let m=gradient of the normal line then the equaion is
    y+2=m(x-1)
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    Integrate  f'(x) and you will get  f(x) . Use the fact that the curve passes through the point (1,-2) to find the constant of integration, c.
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    (Original post by B_9710)
    Integrate  f'(x) and you will get  f(x) . Use the fact that the curve passes through the point (1,-2) to find the constant of integration, c.
    Thank you


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    (Original post by Dr Cobbold)
    Thank you


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    You are, ahhem, welcome.
 
 
 
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