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    Can someone help me with these questions as we've never done examples involving a function on both sides:

    2 sin(theta) = 3 cos(theta)
    and
    2 - cos(theta) = 2 sin^2(theta)

    Shorten theta=x if you want
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    (Original post by not_lucas1)
    Can someone help me with these questions as we've never done examples involving a function on both sides:

    2 sin \theta = 3 cos \theta and 2 - \cos \theta = 2 \sin ^2 \theta

    Shorten \theta=x if you want
    For the first one, recall that \tan \theta = \dfrac{\sin \theta}{\cos \theta}

    For the second one, can you think of a trig identity linking \sin ^2 \theta, \cos ^2 \theta and 1?
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    (Original post by Kvothe the arcane)
    For the first one, recall that \tan \theta = \dfrac{\sin \theta}{\cos \theta}

    For the second one, can you think of a trig identity linking \sin ^2, \cos ^2 and 1?
    honestly all we've done on these graphs is finding the answers when given an example. We haven't learnt anything like that so I'm not so sure why they set us this homework
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    (Original post by not_lucas1)
    honestly all we've done on these graphs is finding the answers when given an example. We haven't learnt anything like that so I'm not so sure why they set us this homework
    Oh, wow I see.

    So you've not covered any trig identities?
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    (Original post by Kvothe the arcane)
    Oh, wow I see.

    So you've not covered any trig identities?
    No, we haven't. I think I'm just going to leave this homework until we actually learn it, thanks for the help anyway
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    What are the odds, we learnt it today. We had the homework set on Monday for friday then it turns out they set us the wrong homework
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    (Original post by not_lucas1)
    What are the odds, we learnt it today. We had the homework set on Monday for friday then it turns out they set us the wrong homework
    Oh okay. Well good luck with the solutions.
 
 
 
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