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    http://www.math.tamu.edu/~tvogel/gallery/node3.html

    Is this explanation enough justification for this argument.

    I am also interested in figuring out who Tom implemented the "mod" argument style in his explanation.
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    (Original post by Mihael_Keehl)
    http://www.math.tamu.edu/~tvogel/gallery/node3.html

    Is this explanation enough justification for this argument.

    I am also interested in figuring out who Tom implemented the "mod" argument style in his explanation.
    All you need to do is take a bounded function \phi(x) which is everywhere discontinuous then let f(x) = x\phi(x) to get a function that is discontinuous everywhere except 0 \, you can see why this is obviously true.

    The justification given is enough, yeah. Depends on how much rigour you want, you could go full blown epsilon-delta if you wish.
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    (Original post by Zacken)
    All you need to do is take a bounded function \phi(x) which is everywhere discontinuous then let f(x) = x\phi(x) to get a function that is discontinuous everywhere except 0 \, you can see why this is obviously true.

    The justification given is enough, yeah. Depends on how much rigour you want, you could go full blown epsilon-delta if you wish.
    Thank you. I follow it, only interested to see how he implemented this into his explanation.

    thnx

    one more thing

    R \ Q in mathematical notation does that mean the real numbers which are not rational numbers?
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    (Original post by Mihael_Keehl)
    R \ Q in mathematical notation does that mean the real numbers which are not rational numbers?
    Yes. Another way of saying this is "irrational numbers".
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    (Original post by Zacken)
    Yes. Another way of saying this is "irrational numbers".
    lmao ofc ty
 
 
 
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