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# Function contunous at only 1 point qq watch

1. http://www.math.tamu.edu/~tvogel/gallery/node3.html

Is this explanation enough justification for this argument.

I am also interested in figuring out who Tom implemented the "mod" argument style in his explanation.
2. (Original post by Mihael_Keehl)
http://www.math.tamu.edu/~tvogel/gallery/node3.html

Is this explanation enough justification for this argument.

I am also interested in figuring out who Tom implemented the "mod" argument style in his explanation.
All you need to do is take a bounded function which is everywhere discontinuous then let to get a function that is discontinuous everywhere except you can see why this is obviously true.

The justification given is enough, yeah. Depends on how much rigour you want, you could go full blown epsilon-delta if you wish.
3. (Original post by Zacken)
All you need to do is take a bounded function which is everywhere discontinuous then let to get a function that is discontinuous everywhere except you can see why this is obviously true.

The justification given is enough, yeah. Depends on how much rigour you want, you could go full blown epsilon-delta if you wish.
Thank you. I follow it, only interested to see how he implemented this into his explanation.

thnx

one more thing

R \ Q in mathematical notation does that mean the real numbers which are not rational numbers?
4. (Original post by Mihael_Keehl)
R \ Q in mathematical notation does that mean the real numbers which are not rational numbers?
Yes. Another way of saying this is "irrational numbers".
5. (Original post by Zacken)
Yes. Another way of saying this is "irrational numbers".
lmao ofc ty

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