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    On AQA Jan 13 question 6, I don't understand why you don't integrate 1/216(t^3), I thought the area under the curve was probability 1 and therefore to find 0.9, you integrated 1/216(t^3) and put it equals to 0.9. The mark scheme just says to put it equal to 0.9 without integrating... I am very confused.

    Thanks.

    Links to paper and mark scheme:

    http://filestore.aqa.org.uk/subjects...B-QP-JAN13.PDF
    http://filestore.aqa.org.uk/subjects...W-MS-JAN13.PDF
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    Anyone? It's only a quick question I think...
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    The capital F means it is the cumulative total so it has already been integrated meaning that you don't have to integrate as well if it was f(T) then you would have to integrate. You probably assumed it was a p.d.f
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    (Original post by 2014_GCSE)
    On AQA Jan 13 question 6, I don't understand why you don't integrate 1/216(t^3), I thought the area under the curve was probability 1 and therefore to find 0.9, you integrated 1/216(t^3) and put it equals to 0.9. The mark scheme just says to put it equal to 0.9 without integrating... I am very confused.

    Thanks.

    Links to paper and mark scheme:

    http://filestore.aqa.org.uk/subjects...B-QP-JAN13.PDF
    http://filestore.aqa.org.uk/subjects...W-MS-JAN13.PDF
    You've confused CDF and PMF. CDF is the integral of PMF. F(t) = \displaystyle\int_{0}^t f(t)dt.

    You're given F(the CDF) in the question, so it's already been integrated.
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    (Original post by juliusjbs)
    The capital F means it is the cumulative total so it has already been integrated meaning that you don't have to integrate as well if it was f(T) then you would have to integrate. You probably assumed it was a p.d.f
    (Original post by morgan8002)
    You've confused CDF and PMF. CDF is the integral of PMF. F(t) = \displaystyle\int_{0}^t f(t)dt.

    You're given F(the CDF) in the question, so it's already been integrated.
    Brilliant, thanks to both of you!
 
 
 
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