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# C2 trig question watch

1. How is:

(sinx/cosx)+(cosx/sinx) = (sin^2x+cos^2x)/sinxcosx

and

(1/cosx)-cosx = (1-cos^x)/cosx

I'm really confused.
How is:

(sinx/cosx)+(cosx/sinx) = (sin^2x+cos^2x)/sinxcosx

and

(1/cosx)-cosx = (1-cos^x)/cosx

I'm really confused.
3. Oh i see now. For the second equation all you have to do was make the denominator the same.
4. First one:
LHS=(sinx/cosx)+(cosx/sinx)
put them over the same denominater:
LHS=(sin^2x/cosxsinx)+(cos^2x)/cosxsinx)
LHS=(sin^2x+cos^2x)/cosxsinx = RHS

You've got the second one?
5. (Original post by Genevieve1)

You've got the second one?
Heya! We try and not give full solutions on this forum, I've seen your posts on a few other threads and just wanted to let you know that it was against forum guidelines. :-)

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Updated: March 11, 2016
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