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    • Thread Starter
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    How is:

    (sinx/cosx)+(cosx/sinx) = (sin^2x+cos^2x)/sinxcosx

    and

    (1/cosx)-cosx = (1-cos^x)/cosx

    I'm really confused.
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    (Original post by CookieHero)
    How is:

    (sinx/cosx)+(cosx/sinx) = (sin^2x+cos^2x)/sinxcosx

    and

    (1/cosx)-cosx = (1-cos^x)/cosx

    I'm really confused.
    by adding the fractions
    • Thread Starter
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    Oh i see now. For the second equation all you have to do was make the denominator the same.
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    First one:
    LHS=(sinx/cosx)+(cosx/sinx)
    put them over the same denominater:
    LHS=(sin^2x/cosxsinx)+(cos^2x)/cosxsinx)
    LHS=(sin^2x+cos^2x)/cosxsinx = RHS

    You've got the second one?
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    (Original post by Genevieve1)

    You've got the second one?
    Heya! We try and not give full solutions on this forum, I've seen your posts on a few other threads and just wanted to let you know that it was against forum guidelines. :-)
 
 
 
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Updated: March 11, 2016
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