c4 differentiation

hey, could some1 help me out on this qsn..

a curve has the equation 4cosX + 2sinY=3
show that dy/dx = 2sinXsecY...im gettin 2sinX/(cosY-1) and i cant see where im goin wrong

ta

Reply 1

*bobo*

-4sinX +2cosY (dY/dX)=0
=> cosY(dY/dX)=2sinX
=>dY/dX= 2sinXsecY

Reply 2

TEE001

oh, thanks a lot..i was writtin it as : -2sinX + cosdy/dx = dy/dx :frown:

Reply 3

lesususu

*bobo*

-4sinX +2cosY (dY/dX)=0
=> cosY(dY/dX)=2sinX
=>dY/dX= 2sinXsecY

Your in Year 11! :eek:

Very impressive

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