# Edexcel S3 - Wednesday 25th May AM 2016

Watch
Announcements
#1

And S3 wouldn't be S3 without it clashing with another module, and this year it clashes with C2.

Here are some resources, inspired by resources from the thread of the previous year.

Madasmaths - awesome website for loads of things for all of your exams, with a few topics that come up in S3.

FMSP revision page - some videos to watch about the specification and a specific set of exam questions.

If there is demand I can start an S4 thread as well..!

And if you have any questions, fire away!

2015 S3 PAPER FROM EDEXCEL'S WEBSITE:

QP

MS:

Model Solutions courtesy of Zacken
2
4 years ago
#2
Thanks for making the thread, please could you explain why on question 2a of this paper https://869d950bf149eefd5cd2652b4001...%20Edexcel.pdf the bias can be plus or minus a/2 as I thought the bias would only be positive? Thanks
0
4 years ago
#3
(Original post by economicss)
Thanks for making the thread, please could you explain why on question 2a of this paper https://869d950bf149eefd5cd2652b4001...%20Edexcel.pdf the bias can be plus or minus a/2 as I thought the bias would only be positive? Thanks
I think it might just be the mark scheme being lenient.
0
4 years ago
#4
(Original post by aymanzayedmannan)
I think it might just be the mark scheme being lenient.
I see, thank you! I don't suppose you could explain how to do question 2c please https://869d950bf149eefd5cd2652b4001...%20Edexcel.pdf I really can't get my head around it! Thanks
0
4 years ago
#5
In. :-)
0
4 years ago
#6
(Original post by economicss)
Thanks for making the thread, please could you explain why on question 2a of this paper https://869d950bf149eefd5cd2652b4001...%20Edexcel.pdf the bias can be plus or minus a/2 as I thought the bias would only be positive? Thanks
It's very simple! You know that is an unbiased estimator of the parameter and the data given to you has been obtained from , so the data is also biased. You must now find the mean, , from the data given by using the formula and since you want to find the unbiased estimator value of , you use the function of . Can you take it from here?
1
4 years ago
#7
(Original post by aymanzayedmannan)
It's very simple! You know that is an unbiased estimator of the parameter and the data given to you has been obtained from , so the data is also biased. You must now find the mean, , from the data given by using the formula and since you want to find the unbiased estimator value of , you use the function of . Can you take it from here?
Many thanks! I don't suppose you could explain question 2c on that paper aswell please? https://869d950bf149eefd5cd2652b4001...%20Edexcel.pdf Thank you
0
4 years ago
#8
Could anyone explain please how you would know what significance level to use in question 6c, is it concluded as not significant because it's below the critical value of 11.345 obtained in part a? https://drive.google.com/folderview?...&usp=drive_web Thanks
0
#9
(Original post by economicss)
Many thanks! I don't suppose you could explain question 2c on that paper aswell please? https://869d950bf149eefd5cd2652b4001...%20Edexcel.pdf Thank you
I'm not sure if you have solved this yet, but think about the links between the parts.

(Original post by economicss)
Could anyone explain please how you would know what significance level to use in question 6c, is it concluded as not significant because it's below the critical value of 11.345 obtained in part a? https://drive.google.com/folderview?...&usp=drive_web Thanks
What an awful/ambiguous question

I would go with the 1% given in part a).
0
#10
(Original post by HT12345)
Can anyone help me with this question (part b) on goodness of fit?

A pesticide was tested by applying it in the form of a spray to 50 samples of 5 flies. The numbers of dead flies after 1 hour were then counted with the following results:

Number of dead flies: 0, 1, 2, 3, 4, 5
Frequency 1, 1, 5, 11, 24, 8

a) Calculate the probability that a fly dies when sprayed. (Answer: 0.72)
b) Using a significance level of 5%, test to see if these data could be modelled by a binomial distribution.
What have you tried?
0
4 years ago
#11
Ooh Im taking this. S3 aint too bad. S4 is a boring piece of ****.

Posted from TSR Mobile
1
4 years ago
#12
What's S2 like?
0
4 years ago
#13
(Original post by Zacken)
In. :-)
Have a look at this question what is ur answer to 7d?

7d i disagree with the book answer.
Lets say -1/2X is outside the sum(they shidve used brackets tbh).

Posted from TSR Mobile
0
4 years ago
#14
If Z=X1+X2+X3 where X1,2,3 have the same distribution
Which method is correct
Var(z)=Var(3Xi)=9Var(Xi)
Var(z)=Var(X1)+Var(X2) etc

Posted from TSR Mobile
0
4 years ago
#15
(Original post by physicsmaths)
Have a look at this question what is ur answer to 7d?

7d i disagree with the book answer.
Lets say -1/2X is outside the sum(they shidve used brackets tbh).

Posted from TSR Mobile
This is how I done it

Is it alright?
0
4 years ago
#16
(Original post by aymanzayedmannan)
This is how I done it

Is it alright?
Yeh it is correct
But why can't
y1+y2+y3=3y1 or y2,3that's where my mistake was

Posted from TSR Mobile
0
4 years ago
#17
(Original post by physicsmaths)
If Z=X1+X2+X3 where X1,2,3 have the same distribution
Which method is correct
Var(z)=Var(3Xi)=9Var(Xi)
Var(z)=Var(X1)+Var(X2) etc

Posted from TSR Mobile
If then

There's a difference between (3 samples being taken) rather than (scaling the distribution by 3).
0
4 years ago
#18
(Original post by Zacken)
If then

There's a difference between (3 samples being taken) rather than (scaling the distribution by 3).
That last line was what I was looking for, cheers mate.

Posted from TSR Mobile
0
4 years ago
#19
(Original post by physicsmaths)
That last line was what I was looking for, cheers mate.

Posted from TSR Mobile
Once you know that, life becomes a hell of a lot easier, that's how you can derive distributions of the mean for samples.

You take samples then scale it by so we have:

So the expected value of the mean is the same as the expect value of the distribution.

You can do something similar with variance:

This shows that the more samples you take, the smaller your variance becomes - which is what we expect.
0
4 years ago
#20
(Original post by physicsmaths)
Yeh it is correct
But why can't
y1+y2+y3=3y1 or y2,3that's where my mistake was

Posted from TSR Mobile
There's a little note on page 3 which says it can't be equal to that but I don't really know of a proof.. There's a proof here though, but I don't get it

Generally

Zacken do you know why they do it like this?

EDIT II: thank you, that gives me a more intuitive understanding of it.
1
X

new posts
Back
to top

view all
Latest
My Feed

### Oops, nobody has postedin the last few hours.

Why not re-start the conversation?

see more

### See more of what you like onThe Student Room

You can personalise what you see on TSR. Tell us a little about yourself to get started.

### Poll

Join the discussion

Yes, my partner and I are struggling (41)
7.9%
Yes, my partner and I broke up (40)
7.71%
Yes, it's hard being around my family so much (124)
23.89%
Yes, I'm feeling lonely isolating alone (73)
14.07%
No, nothing has changed (159)
30.64%
No, it's helped improve my relationships (82)
15.8%