Hey there! Sign in to join this conversationNew here? Join for free
x Turn on thread page Beta
    Offline

    2
    ReputationRep:
    (Original post by It'sPhil...)
    To generalise the result try: Prove that for every integer k, with k>1

    (sum over r >= 1) 1 / [r(r + 1)(r + 3)...(r + k)] = 1/(k!k)
    That's a neat result!
    You certainly no longer need a script or computer program
    Offline

    2
    ReputationRep:
    (Original post by It'sPhil...)
    To generalise the result try: Prove that for every integer k, with k>1

    (sum over r >= 1) 1 / [r(r + 1)(r + 3)...(r + k)] = 1/(k!k)
    Hmm, no one's done it yet.
    See below.
    Attached Images
  1. File Type: pdf neat_sum.pdf (41.9 KB, 237 views)
 
 
 
Turn on thread page Beta
Updated: June 27, 2004
Do I go to The Streets tomorrow night?
Useful resources

Make your revision easier

Maths

Maths Forum posting guidelines

Not sure where to post? Read the updated guidelines here

Equations

How to use LaTex

Writing equations the easy way

Student revising

Study habits of A* students

Top tips from students who have already aced their exams

Study Planner

Create your own Study Planner

Never miss a deadline again

Polling station sign

Thinking about a maths degree?

Chat with other maths applicants

Can you help? Study help unanswered threads

Groups associated with this forum:

View associated groups

The Student Room, Get Revising and Marked by Teachers are trading names of The Student Room Group Ltd.

Register Number: 04666380 (England and Wales), VAT No. 806 8067 22 Registered Office: International House, Queens Road, Brighton, BN1 3XE

Write a reply...
Reply
Hide
Reputation gems: You get these gems as you gain rep from other members for making good contributions and giving helpful advice.