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EVEN MOAR enthalpy problems watch

1. how to do question 2 part c?

Samba123 EricPiphany
Attached Files
2. 2.1 Exercise 1 - measuring enthalpy changes.doc (26.5 KB, 94 views)
3. (Original post by thefatone)
how to do question 2 part c?

Samba123 EricPiphany
Magnesium becomes limiting reagent (also your tags don't work)
4. (Original post by thefatone)
how to do question 2 part c?

Samba123 EricPiphany
How much Cu reacts? And you know the molar enthalpy change of the reaction already.
5. (Original post by samb1234)
Magnesium becomes limiting reagent (also your tags don't work)
right so turns out when you edit tags in they don't work, beautiful. i'll try to remember and put them in next time xD
6. (Original post by samb1234)
Magnesium becomes limiting reagent (also your tags don't work)
7. (Original post by EricPiphany)
How much Cu reacts? And you know the molar enthalpy change of the reaction already.
1 mol of Cu reacts?

so atm i have 9.676.7=m*4.18*delta T
8. (Original post by thefatone)
1 mol of Cu reacts?

so atm i have 9.676.7=m*4.18*delta T
Why 1 mol?
9. (Original post by EricPiphany)
10. (Original post by EricPiphany)
Why 1 mol?
actually since i have 50 g of Cu could i whap that in the formula?
11. (Original post by thefatone)
right so turns out when you edit tags in they don't work, beautiful. i'll try to remember and put them in next time xD
its the spelling that is the issue lol
12. (Original post by samb1234)
its the spelling that is the issue lol
oh
13. (Original post by samb1234)
Good point
14. (Original post by samb1234)
its the spelling that is the issue lol
OK take this one for me, l wanna do some FP2.
15. (Original post by samb1234)
its the spelling that is the issue lol
help pls
i've done

Mol=Mass/mr
mass=mol*mr
=1*159.6 which is mr of CuSO4

then i did 9676.7/(159.6*4.18) and got 14.5K as change in temp
16. (Original post by thefatone)
help pls
i've done

Mol=Mass/mr
mass=mol*mr
=1*159.6 which is mr of CuSO4

then i did 9676.7/(159.6*4.18) and got 14.5K as change in temp
What did you get for part b?
17. (Original post by thefatone)
help pls
i've done

Mol=Mass/mr
mass=mol*mr
=1*159.6 which is mr of CuSO4

then i did 9676.7/(159.6*4.18) and got 14.5K as change in temp
I'm doing something atm i'll help in 30 mins
18. (Original post by EricPiphany)
What did you get for part b?
..
(Original post by thefatone)
help pls
i've done

Mol=Mass/mr
mass=mol*mr
=1*159.6 which is mr of CuSO4

then i did 9676.7/(159.6*4.18) and got 14.5K as change in temp
19. (Original post by thefatone)
help pls
i've done

Mol=Mass/mr
mass=mol*mr
=1*159.6 which is mr of CuSO4

then i did 9676.7/(159.6*4.18) and got 14.5K as change in temp
Find the number of moles of Mg, then times that by the enthalpy change to get energy change
20. (Original post by EricPiphany)
What did you get for part b?
for part b i got 2.43g which was the right answer
21. (Original post by thefatone)
for part b i got 2.43g which was the right answer
So now you are using 0.8g. (0.8/2.43)*46.3 will give you the new temp. increase.

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