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# Can you help me answer my log question??? watch

1. Really struggling with this question on logs, would appreciate any help!

If you can show me workings, that'd be more beneficial!

Thanks!

(I have done part a, struggling on b!)
Attached Images

2. (Original post by Olmeister)
Really struggling with this question on logs, would appreciate any help!

If you can show me workings, that'd be more beneficial!

Thanks!

(I have done part a, struggling on b!)
Next step for b:
3^-1 = ...
3. (Original post by Bath_Student)
Next step for b:
3^-1 = ...
I'm still confused, I've never done logs before!

Here's where I got to!
L
Attached Images

4. (Original post by Olmeister)
I'm still confused, I've never done logs before!

Here's where I got to!
L
The key thing is that the log now drops.

log_a_(x) = y
Then x = a^y
That's what you must do!
Got me?

It's simply rearranging the expression! So what you've done is good, but just drop the log sign in your updated working.
5. (Original post by Bath_Student)
The key thing is that the log now drops.

log_a_(x) = y
Then x = a^y
That's what you must do!
Got me?

It's simply rearranging the expression! So what you've done is good, but just drop the log sign in your updated working.
Is that right?..
Attached Images

6. (Original post by Olmeister)
Is that right?..
Perfect.
Although, personally, I prefer one fraction. So, I'd leave it as 7/3.

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