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Bobjim12
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#1
http://filestore.aqa.org.uk/subjects...W-QP-JUN11.PDF
Question 5.
I'm sitting on S = 2πy∫√(1 +x^2/(x^2+8))
And i'm struggling to get to what they want me to show.
Help pls
Question 5.
I'm sitting on S = 2πy∫√(1 +x^2/(x^2+8))
And i'm struggling to get to what they want me to show.
Help pls
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Zacken
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#2
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#2
(Original post by Bobjim12)
http://filestore.aqa.org.uk/subjects...W-QP-JUN11.PDF
Question 5.
I'm sitting on S = 2πy∫√(1 +x^2/(x^2+8))
And i'm struggling to get to what they want me to show.
Help pls
http://filestore.aqa.org.uk/subjects...W-QP-JUN11.PDF
Question 5.
I'm sitting on S = 2πy∫√(1 +x^2/(x^2+8))
And i'm struggling to get to what they want me to show.
Help pls
outside the integral sign... correct version:
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Bobjim12
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#3
(Original post by Zacken)
I'm very alarmed by the fact that you have the outside the integral sign... correct version:
I'm very alarmed by the fact that you have the
outside the integral sign... correct version:
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Zacken
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#4
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#4
(Original post by Bobjim12)
i can never tell when we can just ignore the minus root, in this case y has two values............ this makes me sad.
i can never tell when we can just ignore the minus root, in this case y has two values............ this makes me sad.
In either case - y is inside the integral!
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Bobjim12
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#5
(Original post by Zacken)
It would have made no difference had you taken the negative root - you'd get a negative area from which (I hope) you'd take the absolute value of to get the positive answer anyway. But at A-Level, you're nearly always going to be taking the positive root without any justification.
In either case - y is inside the integral!
It would have made no difference had you taken the negative root - you'd get a negative area from which (I hope) you'd take the absolute value of to get the positive answer anyway. But at A-Level, you're nearly always going to be taking the positive root without any justification.
In either case - y is inside the integral!
ok ty
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