# Thermodynamics tables? watch

1. (Original post by ServantOfMorgoth)
How did you get that? Using double interpolation?
no i think double interpolation wasnt correct

i used singular interpolation on the density table

i used the first pressure as 0.1 mega pascals and the second pressure as 0.5 mega pascals and the temp is 250

at the first pressure the density is 0.416 and the second pressure the density is 2.108

p = 0.416 + (2.108-0.416) * (0.4-0.1) / (0.5-0.1) = 1.685

1/p = 1/1.685 = 0.593
Spoiler:
Show
no latex but i cba
no i think double interpolation wasnt correct

i used singular interpolation on the density table

i used the first pressure as 0.1 mega pascals and the second pressure as 0.5 mega pascals and the temp is 250

at the first pressure the density is 0.416 and the second pressure the density is 2.108

p = 0.416 + (2.108-0.416) * (0.4-0.1) / (0.5-0.1) = 1.685

1/p = 1/1.685 = 0.593
Spoiler:
Show
no latex but i cba
OMG I forgot 1/p = v

THANKS!
3. (Original post by ServantOfMorgoth)
OMG I forgot 1/p = v

THANKS!
ay lmao not looking good for your exam
4. (Original post by ServantOfMorgoth)
OMG I forgot 1/p = v

THANKS!
i think the main reason is because the 0.1 and 0.5 are quite far apart something closer like 0.3 and its corresponding density wouldve give an answer closer to the true answer

ay lmao not looking good for your exam

i think the main reason is because the 0.1 and 0.5 are quite far apart something closer like 0.3 and its corresponding density wouldve give an answer closer to the true answer

And yeah thanks
i think the main reason is because the 0.1 and 0.5 are quite far apart something closer like 0.3 and its corresponding density wouldve give an answer closer to the true answer

Exam was great
7. (Original post by ServantOfMorgoth)
Exam was great
W00t!
8. (Original post by ServantOfMorgoth)
Exam was great
Awesome

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