Edexcel FP1 Thread - 20th May, 2016 Watch

Zacken
Badges: 22
Rep:
?
#261
Report 2 years ago
#261
(Original post by xyz9856)
Oh I'm so glad, I was thinking this was maybe written before the specification change? By the way I had a look at the January 2016 IAL F1 paper, there is a question there I just don't understand. Is F1 different to FP1 or is it significantly harder but the same content?.

http://imgur.com/Nu0pRS5
It's the same difficulty but with a teensy bit of different content. Which is precisely what the question you've linked me to is about - that topic is not on spec for FP1, every other questions except this "alpha, beta" stuff is though.
0
quote
reply
alfmeister
Badges: 2
Rep:
?
#262
Report 2 years ago
#262
(Original post by Zacken)
I would have expected it in exact form, no?
oh yeah, my bad. I got the same as you for a . And for b i got square root of (-0.5 + 1/(2^0.5) )


Sorry for lack of proper notation.
0
quote
reply
Zacken
Badges: 22
Rep:
?
#263
Report 2 years ago
#263
(Original post by alfmeister)
oh yeah, my bad. I got the same as you for a . And for b i got square root of (-0.5 + 1/(2^0.5) )


Sorry for lack of proper notation.
Nah, no worries - it's just massively ugly and not a proper question.
0
quote
reply
alfmeister
Badges: 2
Rep:
?
#264
Report 2 years ago
#264
(Original post by Zacken)
Nah, no worries - it's just massively ugly and not a proper question.
Now looking back I can see where you are coming from. However I wanted a bit of a challenge so thought I would try it.
0
quote
reply
xyz9856
Badges: 11
Rep:
?
#265
Report 2 years ago
#265
(Original post by Zacken)
It's the same difficulty but with a teensy bit of different content. Which is precisely what the question you've linked me to is about - that topic is not on spec for FP1, every other questions except this "alpha, beta" stuff is though.
Oh I see, going to finish the rest of that paper now. I was a bit disheartened at first and stopped in search of the solution. Thanks again.
0
quote
reply
economicss
Badges: 3
Rep:
?
#266
Report 2 years ago
#266
(Original post by alfmeister)
Posted from TSR Mobile
Sure, I did a different example so that you can try and attempt the question in the paper again.

Attachment 529671
Thanks so much! What did you get as your answers for questions 3 and 7?
0
quote
reply
alfmeister
Badges: 2
Rep:
?
#267
Report 2 years ago
#267
(Original post by economicss)
Thanks so much! What did you get as your answers for questions 3 and 7?
No worries, for 7 I got it was an anticlockwise rotation 45 degrees and an enlargement by a scale factor of 3.

For 3 I think I got -4n^2 +12n +8.

What did you get?
0
quote
reply
economicss
Badges: 3
Rep:
?
#268
Report 2 years ago
#268
(Original post by alfmeister)
No worries, for 7 I got it was an anticlockwise rotation 45 degrees and an enlargement by a scale factor of 3.

For 3 I think I got -4n^2 +12n +8.

What did you get?
I got the same as you for q7! I struggled with question 3, I got 4n(n+1) so I'm probably wrong! haha
0
quote
reply
alfmeister
Badges: 2
Rep:
?
#269
Report 2 years ago
#269
I don't have time now but tommorow I'll post my working if you wanted to check it out?

Posted from TSR Mobile
0
quote
reply
economicss
Badges: 3
Rep:
?
#270
Report 2 years ago
#270
(Original post by alfmeister)
I don't have time now but tommorow I'll post my working if you wanted to check it out?

Posted from TSR Mobile
Yeah that would be good thanks, I'll post mine in a bit
0
quote
reply
Zacken
Badges: 22
Rep:
?
#271
Report 2 years ago
#271
(Original post by alfmeister)
No worries, for 7 I got it was an anticlockwise rotation 45 degrees and an enlargement by a scale factor of 3.

For 3 I think I got -4n^2 +12n +8.

What did you get?
(Original post by economicss)
Yeah that would be good thanks, I'll post mine in a bit
Bleh, might as well:

Note that (3-r)^2 - (r+1)^2 = 9 - 6r + r^2 - r^2 - 2r - 1 = 8 - 8r

So:

\displaystyle

\begin{align*} \sum_{r=0}^{n} 8 - 8r &= 8 - 8(0) + \sum_{r=1}^n (8-8r) \\&= 8 + 8n - 8 \times \frac{n}{2}(n+1) \\&= 8(n+1) - 4n(n+1) \\&= 4(n+1)(2 - n) \\ & = 4(2n - n^2 +2 -n) \\& = -4n^2 +4n + 8\end{align*}

Did you remember that the sum starts from r=0 and hence the sum of \sum_{r=0}^n 8 = 8(n+1) \neq 8n?
1
quote
reply
alfmeister
Badges: 2
Rep:
?
#272
Report 2 years ago
#272
(Original post by Zacken)
Bleh, might as well:

Note that (3-r)^2 - (r+1)^2 = 9 - 6r + r^2 - r^2 - 2r - 1 = 8 - 8r

So:

\displaystyle

\begin{align*} \sum_{r=0}^{n} 8 - 8r &= 8 - 8(0) + \sum_{r=1}^n (8-8r) \\&= 8 + 8n - 8 \times \frac{n}{2}(n+1) \\&= 8(n+1) - 4n(n+1) \\&= 4(n+1)(2 - n) \\ & = 4(2n - n^2 +2 -n) \\& = -4n^2 +4n + 8\end{align*}

Did you remember that the sum starts from r=0 and hence the sum of \sum_{r=0}^n 8 = 8(n+1) \neq 8n?
Damn it, silly error. Got the right working out but made a simple calculation error of 8n + 4n instead of 8n - 4n. Should have checked over my working again. Thanks
0
quote
reply
Zacken
Badges: 22
Rep:
?
#273
Report 2 years ago
#273
(Original post by alfmeister)
Damn it, silly error. Got the right working out but made a simple calculation error of 8n + 4n instead of 8n - 4n. Should have checked over my working again. Thanks
Ah, that's okay then - as long as your concepts are solid.
0
quote
reply
economicss
Badges: 3
Rep:
?
#274
Report 2 years ago
#274
(Original post by Zacken)
Bleh, might as well:

Note that (3-r)^2 - (r+1)^2 = 9 - 6r + r^2 - r^2 - 2r - 1 = 8 - 8r

So:

\displaystyle

\begin{align*} \sum_{r=0}^{n} 8 - 8r &= 8 - 8(0) + \sum_{r=1}^n (8-8r) \\&= 8 + 8n - 8 \times \frac{n}{2}(n+1) \\&= 8(n+1) - 4n(n+1) \\&= 4(n+1)(2 - n) \\ & = 4(2n - n^2 +2 -n) \\& = -4n^2 +4n + 8\end{align*}

Did you remember that the sum starts from r=0 and hence the sum of \sum_{r=0}^n 8 = 8(n+1) \neq 8n?
Thanks for showing the working, made the silly mistake of not working the r=0 term out separately!
0
quote
reply
Zacken
Badges: 22
Rep:
?
#275
Report 2 years ago
#275
(Original post by economicss)
Thanks for showing the working, made the silly mistake of not working the r=0 term out separately!
No worries!
0
quote
reply
tazza ma razza
Badges: 19
Rep:
?
#276
Report 2 years ago
#276
Anybody got any further qns on conics - the ones listed by kingaaran don't have answers...
0
quote
reply
Reeyap
Badges: 1
Rep:
?
#277
Report 2 years ago
#277
Hii guys
Question; under proof by induction, is it necessary to write the whole essay conclusion like the one in the FP1 Edexcel text book or is there a summarised one that could still get the marks for the conclusion?
0
quote
reply
math42
Badges: 19
Rep:
?
#278
Report 2 years ago
#278
(Original post by Reeyap)
Hii guys
Question; under proof by induction, is it necessary to write the whole essay conclusion like the one in the FP1 Edexcel text book or is there a summarised one that could still get the marks for the conclusion?
"So if the statement is true for n, then it is true for n + 1; as it is true for n = 1 it is true for all n by induction" sounds sufficient.
1
quote
reply
Reeyap
Badges: 1
Rep:
?
#279
Report 2 years ago
#279
(Original post by 13 1 20 8 42)
"So if the statement is true for n, then it is true for n + 1; as it is true for n = 1 it is true for all n by induction" sounds sufficient.
Ohh alright
thank youu
0
quote
reply
math42
Badges: 19
Rep:
?
#280
Report 2 years ago
#280
(Original post by Reeyap)
Ohh alright
thank youu
Though I doubt what I said wouldn't be enough, I'd advise looking at what kind of conclusions are on the mark schemes to be on the safe side. In general markers apply the scheme "positively", but always good to check...
0
quote
reply
X

Reply to thread

Attached files
Write a reply...
Reply
new posts
Latest
My Feed

See more of what you like on
The Student Room

You can personalise what you see on TSR. Tell us a little about yourself to get started.

Personalise

University open days

  • University of Lincoln
    Brayford Campus Undergraduate
    Wed, 12 Dec '18
  • Bournemouth University
    Midwifery Open Day at Portsmouth Campus Undergraduate
    Wed, 12 Dec '18
  • Buckinghamshire New University
    All undergraduate Undergraduate
    Wed, 12 Dec '18

Do you like exams?

Yes (144)
18.56%
No (471)
60.7%
Not really bothered about them (161)
20.75%

Watched Threads

View All