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    (Original post by kingaaran)
    Oh no I copied it out from my workings wrong: 2r^2 + 1225/3468 r - (4742591/3668).
    this is what I did http://www.thestudentroom.co.uk/atta...9&d=1463079399 could you point out any errors
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    (Original post by Patrick2810)
    this is what I did http://www.thestudentroom.co.uk/atta...9&d=1463079399 could you point out any errors
    Oh ignore me completely! I was looking at one of my earlier versions the worksheet. You're correct
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    Has anyone got a worked solution to question 15 please http://crashmaths.com/wp-content/upl...-Worksheet.pdf struggling to get my head around it! Thanks
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    Do you have the answer to the question?

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    (Original post by alfmeister)
    Do you have the answer to the question?

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    No, unfortunately there's no mark scheme for these worksheets
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    Posted from TSR Mobile

    I have tried to work through but not sure if I have the right answer
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    (Original post by alfmeister)
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    I have tried to work through but not sure if I have the right answer
    Please could you post your working?
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    (Original post by economicss)
    Has anyone got a worked solution to question 15 please http://crashmaths.com/wp-content/upl...-Worksheet.pdf struggling to get my head around it! Thanks
    This question has added years on to me
    so we know it is a parallelogram, therefore, i made some equations using these facts and modelling c as a=bi
    OC=AB
    OA=CB
    OB^2+CA^2=2(OA^2+CB^2)

    a^2 +b^2=160
    84-5b=6a

    i have put the equations in order in which i developed them from the facts

    i used all these equations to get a is 4 and b is 12

    sorry if my explanation is bad
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    (Original post by wania98)
    This question has added years on to me
    so we know it is a parallelogram, therefore, i made some equations using these facts and modelling c as a=bi
    OC=AB
    OA=CB
    CA=OB

    a^2 +b^2=160
    84-5b=6a
    14b-4a=152

    i have put the equations in order in which i developed them from the facts

    i used all these equations to get a is 4 and b is 12

    sorry if my explanation is bad
    Haha I know how you feel! Where did you get the 160 from, did you use a sketch at all? Struggling to visualise it!
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    (Original post by economicss)
    Haha I know how you feel! Where did you get the 160 from, did you use a sketch at all? Struggling to visualise it!
    yh but my phone is out of battery
    (AB)^2=(OC)^2

    (AB)^2= (6-2)^2 +(5--7)^2
    (AB)^2= 4^2 + 12^2
    (AB)^2=160

    (OC)^2=(a-o)^2+(b-0)^2
    (OC)^2=a^2+b^2
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    Name:  1463088129984.jpg
Views: 146
Size:  29.9 KB

    I drew a diagram and found the displacement of point B from A. Then I knew that point C will be displayed the same distance from the origin as it is the opposite side of BA so I was able to deduce the coordinate of C.
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    (Original post by economicss)
    Haha I know how you feel! Where did you get the 160 from, did you use a sketch at all? Struggling to visualise it!
    (Original post by wania98)
    ...
    \vec{OC} = \vec{AB} = 4 + 12i
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    (Original post by alfmeister)
    Name:  1463088129984.jpg
Views: 146
Size:  29.9 KB

    I drew a diagram and found the displacement of point B from A. Then I knew that point C will be displayed the same distance from the origin as it is the opposite side of BA so I was able to deduce the coordinate of C.
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    5--7 = 5 +7 = 12 \neq 13
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    (Original post by Zacken)
    5--7 = 5 +7 = 12 \neq 13
    I think i got it wrong so embarrassed:bricks:
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    (Original post by wania98)
    yh but my phone is out of battery
    (AB)^2=(OC)^2

    (AB)^2= (6-2)^2 +(5--7)^2
    (AB)^2= 4^2 + 12^2
    (AB)^2=160

    (OC)^2=(a-o)^2+(b-0)^2
    (OC)^2=a^2+b^2
    i think im wrong sorry
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    (Original post by wania98)
    i think im wrong sorry
    You got 4 + 12i as well, didn't you? It just looks like your method was a little contrived.
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    (Original post by Zacken)
    You got 4 + 12i as well, didn't you? It just looks like your method was a little contrived.
    soz i thought you put b is 13 , night brain is kicking in
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    Oh yh silly mistake again, you can see my idea though. My bad again, sorry.

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    (Original post by alfmeister)
    Oh yh silly mistake again, you can see my idea though. My bad again, sorry.

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    Yeah, I could see it was just a silly typo, only corrected you because I didn't want anybody to get confused. Don't apologise!
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    Posted from TSR Mobile

    I need to take my time when trying to help people, I'll review my answers before posting them now because as you said it might confuse people.
 
 
 
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