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    (Original post by Zacken)
    It'll take about 5 minutes to learn, it's really nothing major.
    yeah, I think i've got it now

    So we would be expected to apply stuff we've learnt from C1 and C2 as well?- asking cos some bits I've forgotten from last year- Thanks
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    (Original post by thesmallman)
    yeah, I think i've got it now

    So we would be expected to apply stuff we've learnt from C1 and C2 as well?- asking cos some bits I've forgotten from last year- Thanks
    Yes, certainly.
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    (Original post by Zacken)
    You would need to differentiate every time. You'd get no marks for quoting it. Memorising that bit was useless, I'm afraid.
    Well it's really not that difficult to derive...
    xy = c^2

    y = c^2x^-1
    dy/dx = -c^2/x^2
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    (Original post by iMacJack)
    Well it's really not that difficult to derive...
    xy = c^2

    y = c^2x^-1
    dy/dx = -c^2/x^2
    Bit more complicated than need be.

    xy = c^2

    y + xdy/dx = 0
    dy/dx = -y/x.
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    (Original post by Zacken)
    Bit more complicated than need be.

    xy = c^2

    y + xdy/dx = 0
    dy/dx = -y/x.
    That is in a way which I've not learnt though isn't it?

    Either way - I find my way a bit easier haha
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    (Original post by iMacJack)
    That is in a way which I've not learnt though isn't it?

    Either way - I find my way a bit easier haha
    Implicit differentiation.
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    (Original post by iMacJack)
    That is in a way which I've not learnt though isn't it?

    Either way - I find my way a bit easier haha
    Oh, you haven't learnt that yet? Makes sense. I never know what bit of what is in what module 'cause I've studied them all simultaneously because circumstances. Sorry!
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    (Original post by Zacken)
    Oh, you haven't learnt that yet? Makes sense. I never know what bit of what is in what module 'cause I've studied them all simultaneously because circumstances. Sorry!
    Haha! Isn't that implicit differentiation? I'm an AS candidate, we don't learn that until C4 (or 3??)
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    (Original post by iMacJack)
    Haha! Isn't that implicit differentiation? I'm an AS candidate, we don't learn that until C4 (or 3??)
    I do A2 Maths and still do your way
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    (Original post by iMacJack)
    Haha! Isn't that implicit differentiation? I'm an AS candidate, we don't learn that until C4 (or 3??)
    It's taught in C4, my preferred method is parametric differentiation, if the curve is defined by another parameter, it's much faster.
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    Is there a difference in content between the F1 and FP1 papers?


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    (Original post by Glavien)
    Is there a difference in content between the F1 and FP1 papers?


    Posted from TSR Mobile
    I think F1 might involve some extra stuff on roots of polynomials. Don't quote me on that though
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    For question 10(ii) of the January 2014 FP1 IAL paper would this get the marks for the induction bit of the question? It doesn't show my method in the mark scheme but it seems to work.Thanks!

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    (Original post by Glavien)
    For question 10(ii) of the January 2014 FP1 IAL paper would this get the marks for the induction bit of the question? It doesn't show my method in the mark scheme but it seems to work.Thanks!
    Yeah, it's basically the same thing.

    (Original post by 13 1 20 8 42)
    I think F1 might involve some extra stuff on roots of polynomials. Don't quote me on that though
    That's correct, yes.
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    (Original post by Zacken)
    Yeah, it's basically the same thing.



    That's correct, yes.
    Thanks!
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    If A and B are matrices what will M =(A +B)(2A-B) expand out too? How do you know the order to multiply the matrices?
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    (Original post by iMacJack)
    Haha! Isn't that implicit differentiation? I'm an AS candidate, we don't learn that until C4 (or 3??)
    I prefer using implicit differentiation. It's a lot quicker, in my experience, to use implicit differentiation.
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    (Original post by Glavien)
    If A and B are matrices what will M =(A +B)(2A-B) expand out too? How do you know the order to multiply the matrices?
    In FP1, just evaluate the two brackets first and then multiply them together. Expanding them out and will be even more work than that...

    But: (A+B)(2A-B) = 2A^2 - AB + 2BA - B^2
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    (Original post by Zacken)
    In FP1, just evaluate the two brackets first and then multiply them together. Expanding them out and will be even more work than that...

    But: (A+B)(2A-B) = 2A^2 - AB + 2BA - B^2
    Cool thanks!
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    is there a june 15 r?
 
 
 
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