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# Edexcel FP1 Thread - 20th May, 2016 watch

1. Can someone check my answer to this question please? There's no mark scheme to the question.

Attachment 532983

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2. (Original post by Glavien)
Can someone check my answer to this question please? There's no mark scheme to the question.

Attachment 532983

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Seems good to me, you can always check your answer by see if 2+i squared equals 3 + 4i
3. Any recommendations on what to do after doing all the edexcel papers?
4. (Original post by AmarPatel98)
Any recommendations on what to do after doing all the edexcel papers?
Chill out.
5. (Original post by alfmeister)
Seems good to me, you can always check your answer by see if 2+i squared equals 3 + 4i
Thanks!

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6. Is part b of this question correct?

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7. (Original post by Glavien)
Is part b of this question correct?

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Yes it seems correct however on the second to last line of working why do you have -λ
8. I have no clue what they're doing in this question, can someone please explain?

9. (Original post by fullmetal heart)
I have no clue what they're doing in this question, can someone please explain?

which part don't you understand?
10. (Original post by fullmetal heart)
I have no clue what they're doing in this question, can someone please explain?

for part a

they are multiplying by the inverse of B on each side. So the inverse of B times the identity matrix equuals the inverse of B. Anything multiplied by the identity matrix is the same . And B*B^-1 = I so you get AB= B^-1 then you multiply agin by B^-1 to get A*B*B^-1 =B^-1B^-1
which equals A=B^-1B^-1

Hope that helps
11. (Original post by maruchan)
which part don't you understand?
How they know what to do next
12. (Original post by maruchan)
for part a

they are multiplying by the inverse of B on each side. So the inverse of B times the identity matrix equuals the inverse of B. Anything multiplied by the identity matrix is the same . And B*B^-1 = I so you get AB= B^-1 then you multiply agin by B^-1 to get A*B*B^-1 =B^-1B^-1
which equals A=B^-1B^-1

Hope that helps
Thanks
13. (Original post by fullmetal heart)
Thanks
14. In proof by induction for divisibility proofs, you know how you might typically do
f(k+1) - f(k), find this, and then make f(k+1) the subject

i.e. f(k+1) - f(k) = ABC
so f(k+1) = ABC + f(k)

Can you do f(k+1) + f(k) ???

i.e. f(k+1) + f(k) = ABC
so f(k+1) = ABC - f(k)
15. What's some of the hardest things they could ask?
16. (Original post by AmarPatel98)
In proof by induction for divisibility proofs, you know how you might typically do
f(k+1) - f(k), find this, and then make f(k+1) the subject

i.e. f(k+1) - f(k) = ABC
so f(k+1) = ABC + f(k)

Can you do f(k+1) + f(k) ???

i.e. f(k+1) + f(k) = ABC
so f(k+1) = ABC - f(k)
Do you think you can? I think you can

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17. (Original post by AmarPatel98)
In proof by induction for divisibility proofs, you know how you might typically do
f(k+1) - f(k), find this, and then make f(k+1) the subject

i.e. f(k+1) - f(k) = ABC
so f(k+1) = ABC + f(k)

Can you do f(k+1) + f(k) ???

i.e. f(k+1) + f(k) = ABC
so f(k+1) = ABC - f(k)
Do you understand it?

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18. (Original post by AmarPatel98)
In proof by induction for divisibility proofs, you know how you might typically do
f(k+1) - f(k), find this, and then make f(k+1) the subject

i.e. f(k+1) - f(k) = ABC
so f(k+1) = ABC + f(k)

Can you do f(k+1) + f(k) ???

i.e. f(k+1) + f(k) = ABC
so f(k+1) = ABC - f(k)
Yeah, of course.
19. EDIT: SHOULD READ 'Divisible by 18' not 8

can someone check this pls ... im not sure if this would get full marks. It's from the paper linked below - June 14 IAL F1 - and the method i did it by isn't in the markscheme. Thanks!

https://7cba9babeb0db0ff9468853e0b2d...%20Edexcel.pdf
20. For proof by induction, what does all the notation (e.g. nEZ+) actually mean?

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