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Edexcel FP1 Thread - 20th May, 2016

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Can someone check my answer to this question please? There's no mark scheme to the question.

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Original post by Glavien
Can someone check my answer to this question please? There's no mark scheme to the question.

Attachment not found
ImageUploadedByStudent Room1463476625.290286.jpg


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Seems good to me, you can always check your answer by see if 2+i squared equals 3 + 4i
Any recommendations on what to do after doing all the edexcel papers?
Original post by AmarPatel98
Any recommendations on what to do after doing all the edexcel papers?


Chill out.
Original post by alfmeister
Seems good to me, you can always check your answer by see if 2+i squared equals 3 + 4i


Thanks! :smile:



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Is part b of this question correct?

ImageUploadedByStudent Room1463480460.612780.jpg

ImageUploadedByStudent Room1463480472.089406.jpg


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Original post by Glavien
Is part b of this question correct?

ImageUploadedByStudent Room1463480460.612780.jpg

ImageUploadedByStudent Room1463480472.089406.jpg


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Yes it seems correct however on the second to last line of working why do you have -λ
I have no clue what they're doing in this question, can someone please explain?

image.jpg
Original post by fullmetal heart
I have no clue what they're doing in this question, can someone please explain?

image.jpg


which part don't you understand?
Original post by fullmetal heart
I have no clue what they're doing in this question, can someone please explain?

image.jpg


for part a

they are multiplying by the inverse of B on each side. So the inverse of B times the identity matrix equuals the inverse of B. Anything multiplied by the identity matrix is the same . And B*B^-1 = I so you get AB= B^-1 then you multiply agin by B^-1 to get A*B*B^-1 =B^-1B^-1
which equals A=B^-1B^-1

Hope that helps
Original post by maruchan
which part don't you understand?


How they know what to do next
Original post by maruchan
for part a

they are multiplying by the inverse of B on each side. So the inverse of B times the identity matrix equuals the inverse of B. Anything multiplied by the identity matrix is the same . And B*B^-1 = I so you get AB= B^-1 then you multiply agin by B^-1 to get A*B*B^-1 =B^-1B^-1
which equals A=B^-1B^-1

Hope that helps


Thanks
Original post by fullmetal heart
Thanks

:smile:
In proof by induction for divisibility proofs, you know how you might typically do
f(k+1) - f(k), find this, and then make f(k+1) the subject

i.e. f(k+1) - f(k) = ABC
so f(k+1) = ABC + f(k)

Can you do f(k+1) + f(k) ???

i.e. f(k+1) + f(k) = ABC
so f(k+1) = ABC - f(k)
What's some of the hardest things they could ask?
Original post by AmarPatel98
In proof by induction for divisibility proofs, you know how you might typically do
f(k+1) - f(k), find this, and then make f(k+1) the subject

i.e. f(k+1) - f(k) = ABC
so f(k+1) = ABC + f(k)

Can you do f(k+1) + f(k) ???

i.e. f(k+1) + f(k) = ABC
so f(k+1) = ABC - f(k)


Do you think you can? I think you can

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Original post by AmarPatel98
In proof by induction for divisibility proofs, you know how you might typically do
f(k+1) - f(k), find this, and then make f(k+1) the subject

i.e. f(k+1) - f(k) = ABC
so f(k+1) = ABC + f(k)

Can you do f(k+1) + f(k) ???

i.e. f(k+1) + f(k) = ABC
so f(k+1) = ABC - f(k)


Do you understand it?

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Original post by AmarPatel98
In proof by induction for divisibility proofs, you know how you might typically do
f(k+1) - f(k), find this, and then make f(k+1) the subject

i.e. f(k+1) - f(k) = ABC
so f(k+1) = ABC + f(k)

Can you do f(k+1) + f(k) ???

i.e. f(k+1) + f(k) = ABC
so f(k+1) = ABC - f(k)


Yeah, of course.
IMG-20160517-WA0044.jpgEDIT: SHOULD READ 'Divisible by 18' not 8

can someone check this pls ... im not sure if this would get full marks. It's from the paper linked below - June 14 IAL F1 - and the method i did it by isn't in the markscheme. Thanks!

https://7cba9babeb0db0ff9468853e0b2d0a80708ec59c.googledrive.com/host/0B1ZiqBksUHNYZGxseFBIQkphV0k/June%202014%20(IAL)%20QP%20-%20F1%20Edexcel.pdf
(edited 7 years ago)
For proof by induction, what does all the notation (e.g. nEZ+) actually mean?

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