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# Edexcel FP1 Thread - 20th May, 2016 watch

1. Dropped at least 2 marks, not too fussed though since the grade boundaries will probably be a bit lower than standard.
Don't think it was too tough though
2. (Original post by NotNotBatman)
For the last question, did it say the midpoint lied on the positive x axis or just that it was positive?
Positive x-axis
3. How many marks was 9b worth?
4. Couldn't you say that T^2= T therefore its self inverse???
5. (Original post by oShahpo)
Lied on the positive x axis so y=0
(Original post by midgemeister7)
Positive x-axis
ah, I messed that question up.
6. (Original post by chewitt77)
+-sqr2/2 (+-1/sqr2)
9/2*x^1/2 + 25/2*x^-3/2
12.467 (I double checked this however may still be wrong)
a=38 b=15 c=1
2-2i, -8i, p=-4 q=8
1/p
anti clockwise rotation 45 degree about (0,0) (this may be wrong)
p=-3 q=-9, matrix (0 1 (bottom line 1 0))
a^2 +2a -4 + 4i(a +1), a=-1, sqr5 and 2.03 rad, QR twice the length of OP and QR is parallel to OP
x=15sqr2/4
I put rotation 135 degree anticlockwise, cus when i put 135 back into the cos and sin formula i got the same matrix as the question
And 12.468 3dp
7. (Original post by midgemeister7)
those are all right except the anti-clockwise rotation which was 135 degrees I believe
Yeah I got 135 anti, if you don't put (0,0), will I lose marks, I swear all the matrices are in FP1
8. (Original post by TheRandomGenius)
Couldn't you say that T^2= T therefore its self inverse???
No, T^2 = I, therefore T=T^-1, therefore its selfinverse
9. (Original post by ombtom)
Yes, it was -1. You just had to find the inverse matrix and say that it was the same, i.e. R^-1 = R .'. self-inverse.
My signs for T^-1 was flipped though. Did you get exactly the same signs?
10. I think I've forgot to switch the elements to find inverse R, that's why I couldn't prove it. How many marks was that question?
11. (Original post by NotNotBatman)
I think I've forgot to switch the elements to find inverse R, that's why I couldn't prove it. How many marks was that question?
Just 1 I think, may be2
12. (Original post by Chirstos Ioannou)
How? It's the first time i've seen such a question.
I also had difficulty with this question. Not sure if my ans is correct.
13. (Original post by Sallekmo)
MY friend found one question soo hard he put his paypal email address as the answer. Lol I saw him do it.
sounds like your friend should be taking BTEC media studies not Further maths then...
14. (Original post by AhnafR)
My signs for T^-1 was flipped though. Did you get exactly the same signs?
Did you remember to divide by the determinant (which was -1)?
15. I think I could get 73/75. Lol
16. (Original post by Person18)
Yeah I got 135 anti, if you don't put (0,0), will I lose marks, I swear all the matrices are in FP1
I think might have lost 2 marks there then , because I put pi/4 anti

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17. Sorry yeah thats what I meant- T^2 = I. That would get the mark?
(Original post by anndz3007)
No, T^2 = I, therefore T=T^-1, therefore its selfinverse
18. (Original post by NotNotBatman)
For the last question, did it say the midpoint lied on the positive x axis or just that it was positive?
No it said that the midpoint was on y=-x lol dumbdumb
19. (Original post by Skygliderjack)
It wanted the modulus and argument of z, not z^2+2z
FML I've got that wrong then.
20. (Original post by anonymousGangsta)
sounds like your friend should be taking BTEC media studies not Further maths then...
Lol, you know finding 1 question hard isn't that big of a deal,

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