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# Edexcel FP1 Thread - 20th May, 2016 watch

1. (Original post by AhnafR)
My signs for T^-1 was flipped though. Did you get exactly the same signs?
Yeah, all of the signs changed when swapping a d and the sign of b c, so the -1 determinant changed all of the signs back.
2. (Original post by ws12758)
No it said that the midpoint was on y=-x lol dumbdumb
Don't think it did
3. (Original post by anndz3007)
I put rotation 135 degree anticlockwise, cus when i put 135 back into the cos and sin formula i got the same matrix as the question
And 12.468 3dp
cheers, Im so annoyed seeing every one have it 0.001 different to mine as I checked it twice in the half an hour I had left
4. (Original post by chewitt77)
cheers, Im so annoyed seeing every one have it 0.001 different to mine as I checked it twice in the half an hour I had left
You'll almost definitely only drop 1 mark. Don't worry about it
5. (Original post by chewitt77)
+-sqr2/2 (+-1/sqr2)
9/2*x^1/2 + 25/2*x^-3/2
12.467 (I double checked this however may still be wrong)
a=38 b=15 c=1
2-2i, -8i, p=-4 q=8
1/p
anti clockwise rotation 45 degree about (0,0) (this may be wrong)
p=-3 q=-9, matrix (0 1 (bottom line 1 0))
a^2 +2a -4 + 4i(a +1), a=-1, sqr5 and 2.03 rad, QR twice the length of OP and QR is parallel to OP
x=15sqr2/4
Wait, for the QR and OP I don't remember them being parallel. Wasn't R = -5 on the real axis, P = -1+2i. I don't remember what they were exactly

EDIT:
And Q = -3+4i? Not sure
6. (Original post by midgemeister7)
Don't think it did
It definitely did not. Intersection between y=-x and the gradient was the condition to find the other point I think.
7. (Original post by TheRandomGenius)
Sorry yeah thats what I meant- T^2 = I. That would get the mark?
I dont kbow but that's what i put, i calculated TT and got I, so i put TT= I, TT^-1= I
=>T =T^-1
8. (Original post by Chirstos Ioannou)
Wait i just realized i'm talking about the IAL one, so the GCE was hard?
Is there a different blog for IAL as I did that paper as well
I got K=5
Wbu?
9. Someone please make a Hitler reacts video
10. (Original post by Sallekmo)
Lol dude they wernt 3 marks they were 5 marks each
Nah the very last two questions were 3 each.
11. anyone got a= -1 for z^2+2z ?
12. (Original post by ws12758)
No it said that the midpoint was on y=-x lol dumbdumb
That's a different question.
13. (Original post by Vishna)
Is there a different blog for IAL as I did that paper as well
I got K=5
Wbu?

http://www.thestudentroom.co.uk/show....php?t=4102261
14. (Original post by chewitt77)
cheers, Im so annoyed seeing every one have it 0.001 different to mine as I checked it twice in the half an hour I had left
I was trying to be sure so i literally put all the digits in the calculation in the equation ._. Idk why everyone got .007
15. Does anybody remember how much were the two last sub questions in question 9 worth? 🙄
16. (Original post by oShahpo)
It definitely did not. Intersection between y=-x and the gradient was the condition to find the other point I think.
He made an account just to call someone dumb and got it wrong himself lol

(Original post by annehappy)
anyone got a= -1 for z^2+2z ?
yep
17. (Original post by annehappy)
anyone got a= -1 for z^2+2z ?
Yes
18. (Original post by TheRandomGenius)
Sorry yeah thats what I meant- T^2 = I. That would get the mark?
Yes.
19. (Original post by anndz3007)
I put rotation 135 degree anticlockwise, cus when i put 135 back into the cos and sin formula i got the same matrix as the question
And 12.468 3dp
agreed on 12.468.

Think I wrote mod z as root 5 but arg to 3sf. Looks like I lost one there
20. (Original post by Sophie Wilczek)
Does anybody remember how much were the two last sub questions in question 9 worth? 🙄
nein

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