Hey there! Sign in to join this conversationNew here? Join for free
x Turn on thread page Beta
    Offline

    15
    ReputationRep:
    (Original post by AhnafR)
    My signs for T^-1 was flipped though. Did you get exactly the same signs?
    Yeah, all of the signs changed when swapping a d and the sign of b c, so the -1 determinant changed all of the signs back.
    Offline

    15
    ReputationRep:
    (Original post by ws12758)
    No it said that the midpoint was on y=-x lol dumbdumb
    Don't think it did
    Offline

    1
    ReputationRep:
    (Original post by anndz3007)
    I put rotation 135 degree anticlockwise, cus when i put 135 back into the cos and sin formula i got the same matrix as the question
    And 12.468 3dp
    cheers, Im so annoyed seeing every one have it 0.001 different to mine as I checked it twice in the half an hour I had left
    Offline

    15
    ReputationRep:
    (Original post by chewitt77)
    cheers, Im so annoyed seeing every one have it 0.001 different to mine as I checked it twice in the half an hour I had left
    You'll almost definitely only drop 1 mark. Don't worry about it
    Offline

    3
    ReputationRep:
    (Original post by chewitt77)
    +-sqr2/2 (+-1/sqr2)
    9/2*x^1/2 + 25/2*x^-3/2
    12.467 (I double checked this however may still be wrong)
    a=38 b=15 c=1
    2-2i, -8i, p=-4 q=8
    1/p
    anti clockwise rotation 45 degree about (0,0) (this may be wrong)
    p=-3 q=-9, matrix (0 1 (bottom line 1 0))
    a^2 +2a -4 + 4i(a +1), a=-1, sqr5 and 2.03 rad, QR twice the length of OP and QR is parallel to OP
    x=15sqr2/4
    Wait, for the QR and OP I don't remember them being parallel. Wasn't R = -5 on the real axis, P = -1+2i. I don't remember what they were exactly

    EDIT:
    And Q = -3+4i? Not sure
    Offline

    20
    ReputationRep:
    (Original post by midgemeister7)
    Don't think it did
    It definitely did not. Intersection between y=-x and the gradient was the condition to find the other point I think.
    Offline

    2
    ReputationRep:
    (Original post by TheRandomGenius)
    Sorry yeah thats what I meant- T^2 = I. That would get the mark?
    I dont kbow but that's what i put, i calculated TT and got I, so i put TT= I, TT^-1= I
    =>T =T^-1
    Offline

    1
    ReputationRep:
    (Original post by Chirstos Ioannou)
    Wait i just realized i'm talking about the IAL one, so the GCE was hard?
    Is there a different blog for IAL as I did that paper as well
    I got K=5
    Wbu?
    Offline

    4
    ReputationRep:
    Someone please make a Hitler reacts video
    Offline

    1
    ReputationRep:
    (Original post by Sallekmo)
    Lol dude they wernt 3 marks they were 5 marks each
    Nah the very last two questions were 3 each.
    Offline

    1
    ReputationRep:
    anyone got a= -1 for z^2+2z ?
    • Community Assistant
    Offline

    18
    ReputationRep:
    Community Assistant
    (Original post by ws12758)
    No it said that the midpoint was on y=-x lol dumbdumb
    That's a different question.
    Offline

    15
    ReputationRep:
    (Original post by Vishna)
    Is there a different blog for IAL as I did that paper as well
    I got K=5
    Wbu?
    Someone's made a thread for the IAL paper.

    http://www.thestudentroom.co.uk/show....php?t=4102261
    Offline

    2
    ReputationRep:
    (Original post by chewitt77)
    cheers, Im so annoyed seeing every one have it 0.001 different to mine as I checked it twice in the half an hour I had left
    I was trying to be sure so i literally put all the digits in the calculation in the equation ._. Idk why everyone got .007
    Offline

    2
    ReputationRep:
    Does anybody remember how much were the two last sub questions in question 9 worth? 🙄
    Offline

    15
    ReputationRep:
    (Original post by oShahpo)
    It definitely did not. Intersection between y=-x and the gradient was the condition to find the other point I think.
    He made an account just to call someone dumb and got it wrong himself lol

    (Original post by annehappy)
    anyone got a= -1 for z^2+2z ?
    yep
    Offline

    2
    ReputationRep:
    (Original post by annehappy)
    anyone got a= -1 for z^2+2z ?
    Yes
    Offline

    22
    ReputationRep:
    (Original post by TheRandomGenius)
    Sorry yeah thats what I meant- T^2 = I. That would get the mark?
    Yes.
    Offline

    2
    ReputationRep:
    (Original post by anndz3007)
    I put rotation 135 degree anticlockwise, cus when i put 135 back into the cos and sin formula i got the same matrix as the question
    And 12.468 3dp
    agreed on 12.468.

    Think I wrote mod z as root 5 but arg to 3sf. Looks like I lost one there
    Offline

    0
    ReputationRep:
    (Original post by Sophie Wilczek)
    Does anybody remember how much were the two last sub questions in question 9 worth? 🙄
    nein
 
 
 
Reply
Submit reply
Turn on thread page Beta
Updated: August 18, 2016
Poll
Do you like carrot cake?

The Student Room, Get Revising and Marked by Teachers are trading names of The Student Room Group Ltd.

Register Number: 04666380 (England and Wales), VAT No. 806 8067 22 Registered Office: International House, Queens Road, Brighton, BN1 3XE

Write a reply...
Reply
Hide
Reputation gems: You get these gems as you gain rep from other members for making good contributions and giving helpful advice.