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# Edexcel FP1 Thread - 20th May, 2016 watch

1. (Original post by Pyslocke)
Wait, for the QR and OP I don't remember them being parallel. Wasn't R = -5 on the real axis, P = -1+2i. I don't remember what they were exactly
I can't rember exactly however if you look at OP as being the vector z (as that is what point P was)

Then travelling from the point z^2 two lots of the vector z means they have both travelled in the same direction, just one QR was two lots of z hence travelling twice as far
2. If anybody gets a hold of the paper, I don't mind doing model solutions.
3. Here Are some of the answers I managed to write onto my name sheet:

1) k = +/- sqrt(2)/2
2b) 12.468
3b) a = 38; b = 15; c = 1;
4c) p = -4; q = 8;
6a) 135 anticlockwise
6b) p= -3; q = -9;
7b) a = -1;
7e) parallel
9c) 15*sqrt(2) / 2

please tell me if I am correct on the last two
4. (Original post by anndz3007)
I was trying to be sure so i literally put all the digits in the calculation in the equation ._. Idk why everyone got .007
yeah i made sure I didn't have rounding errors, my calculator could only just do it if I had the powers as decimals instead of fractions. glad someone else got the same as me, just looking unlucky that we're right haha
5. Yeah you're right don't worry

(Original post by ICantFindMyName)
Here Are some of the answers I managed to write onto my name sheet:

1) k = +/- sqrt(2)/2
2b) 12.468
3b) a = 38; b = 15; c = 1;
4c) p = -4; q = 8;
6a) 135 anticlockwise
6b) p= -3; q = -9;
7b) a = -1;
7e) parallel
9c) 15*sqrt(2) / 2

please tell me if I am correct on the last two
6. (Original post by ICantFindMyName)
Here Are some of the answers I managed to write onto my name sheet:

1) k = +/- sqrt(2)/2
2b) 12.468
3b) a = 38; b = 15; c = 1;
4c) p = -4; q = 8;
6a) 135 anticlockwise
6b) p= -3; q = -9;
7b) a = -1;
7e) parallel
9c) 15*sqrt(2) / 2

please tell me if I am correct on the last two
I got all of those mate
7. (Original post by veldt127)
agreed on 12.468.

Think I wrote mod z as root 5 but arg to 3sf. Looks like I lost one there
I'm pretty certain it didn't specify the degree of accuracy for the modulus but did for the argument - I got the same, think it should be fine
8. (Original post by ICantFindMyName)
Here Are some of the answers I managed to write onto my name sheet:

1) k = +/- sqrt(2)/2
2b) 12.468
3b) a = 38; b = 15; c = 1;
4c) p = -4; q = 8;
6a) 135 anticlockwise
6b) p= -3; q = -9;
7b) a = -1;
7e) parallel
9c) 15*sqrt(2) / 2

please tell me if I am correct on the last two
7e for the second mark I think you needed to say QR was twice the length of OP and for 9c I got 15sqr(2)/4
9. Is the markscheme out yet?
10. (Original post by veldt127)
agreed on 12.468.

Think I wrote mod z as root 5 but arg to 3sf. Looks like I lost one there
The wording in that questuon was terrible, i put root 5 and think its reasonable, and then it said put your answer in 3sf, so i put root5=2.something and be like is this what you want edexcel, i'll do whatever you want lol
11. (Original post by jonahz123)
Nah the very last two questions were 3 each.
Yes tha last two questions were , but he said the proof by induction questions, and they were 5 marks each
12. arsey where are ya
13. (Original post by ICantFindMyName)
Here Are some of the answers I managed to write onto my name sheet:

1) k = +/- sqrt(2)/2
2b) 12.468
3b) a = 38; b = 15; c = 1;
4c) p = -4; q = 8;
6a) 135 anticlockwise
6b) p= -3; q = -9;
7b) a = -1;
7e) parallel
9c) 15*sqrt(2) / 2

please tell me if I am correct on the last two
think the last one was 15*sqrt(2)/4
14. (Original post by ws12758)
nein
3 each
15. (Original post by LewisClothier)
Got the inductions with a bit of disgusting work, wasn't nice though, and I realised that the imaginary part=0 in the last 5 minutes so had Five minutes to finish off the question, just about got it all apart from the one marker in part e). I was so annoyed about not knowing how to do that question until I realised though!

Posted from TSR Mobile
exact same thing happened to me i also managed to get the first induction but i only managed to do half of the 2nd induction as i wasn't thinking straight
16. i m confused is both f1 n fp1 discussions goin on in here
n plz link a f1 unofficial markscheme if possible
i think f1 was pretty hard dan fp1 paper
17. This exam made me want to kms.

Wtf was with question 8 and 9.
18. I got 15root2/4 , its the midpoint so you have to devide the whole thing by 2
19. (Original post by anndz3007)
12.468
N/6(38n^2 +15n +1)
X^2 -4x +8
P=-3 q=-9
M = (15root2/4,0)
Only being pedantic, but they explicitly asked for the x-coordinate of 'M', given your value of p. Not the full coordinate, you would still get full marks I'm sure
20. It was a lot harder than last years paper, in my opinion

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