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    (Original post by midgemeister7)
    think the last one was 15*sqrt(2)/4
    ya i got the same too
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    (Original post by anndz3007)
    The wording in that questuon was terrible, i put root 5 and think its reasonable, and then it said put your answer in 3sf, so i put root5=2.something and be like is this what you want edexcel, i'll do whatever you want lol
    Yeah, giving the arg to 3sf was reasonable as it wasn't possible to give it exactly. The modulus could be written exactly though so I was used to writing it as a surd
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    (Original post by mathew daniels)
    What was the geometrical relationship between those lines?

    I put they were parallel, what was the other mark for?

    Also was z^2 -8i ?

    And for the modulus did people get 2.34?
    Apparently it was that the line was double the length or it was translated
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    https://www.youtube.com/watch?v=h1zXCvs_mFk It's out
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    (Original post by Alex6665)
    The easiest paper I have ever done , 75/75 guaranteed
    ????
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    (Original post by Alex6665)
    The easiest paper I have ever done , 75/75 guaranteed
    glad someone agrees, wasnt that hard at all
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    (Original post by chewitt77)
    I can't rember exactly however if you look at OP as being the vector z (as that is what point P was)

    Then travelling from the point z^2 two lots of the vector z means they have both travelled in the same direction, just one QR was two lots of z hence travelling twice as far
    Wow -_-. My value of z^2 on argand diagram was -3+4i and not -3-4i. My bad.
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    (Original post by Moezph)
    Only being pedantic, but they explicitly asked for the x-coordinate of 'M', given your value of p. Not the full coordinate, you would still get full marks I'm sure
    Lol i did calculate the x coordinate only but the working invole putting y=0 so im just gonna leave it there
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    (Original post by anndz3007)
    I got 15root2/4 , its the midpoint so you have to devide the whole thing by 2
    you only have to do (y1 + y2) / 2 and (x1 + x2) / 2

    replicated question and pretty sure answer is 15 sqrt(2) / 2
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    fp1 was bare easy
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    (Original post by ohsammmie)
    did anyone have problem proving the coordinates for a on question 9?
    yes oh my god
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    Please come and vote at
    http://www.thestudentroom.co.uk/show....php?t=4101989
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    (Original post by Orwellianhipster)
    Someone please make a hitler reacts to fp1 vid
    https://www.youtube.com/watch?v=h1zX...&feature=share
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    Everyone getting the x coordinate as 15root2/4 then there's me wondering how to get the value of P lol oops
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    Does anyone remember how many marks the second part of the series question was where you had to show the sum from 2n+1 to 3n for r^2? and what answer did you all get
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    (Original post by ombtom)
    Definitely harder than usual, but not impossible.

    Here are a few of my answers that I can remember:

    k = +/-\sqrt2/2
    12.468
    a = 38, b = 15, c = 1
    p = -4, q = 8 (there was more than one question with p and q)
    135 degrees anticlockwise
    ??? .
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    (Original post by Skygliderjack)
    Yeah I did It was just easier to say root 5
    I'm sure it was 3 dp?
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    (Original post by iMacJack)
    Everyone getting the x coordinate as 15root2/4 then there's me wondering how to get the value of P lol oops
    haha me too how did people even do that
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    (Original post by shuu00)
    I'm sure it was 3 dp?
    That was the argument. 3SF
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    (Original post by a0510300)
    ??? .
    Problem?
 
 
 
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