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    (Original post by tiny hobbit)
    Has taught what? Are you doing IAL or "ordinary" A level?
    "ordinary A-level," I assume you mean knowledge that a quadratic equation in the form  x^2 + bx + c where  \alpha and  \beta are the roots of the equation can be expressed in the form  x^2 - (\alpha+\beta)x + \alpha\beta
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    (Original post by NotNotBatman)
    "ordinary A-level," I assume you mean knowledge that a quadratic equation in the form  x^2 + bx + c where  \alpha and  \beta are the roots of the equation can be expressed in the form  x^2 - (\alpha+\beta)x + \alpha\beta
    The IAL goes a lot further, wanting you to find the equation with roots alpha cubed and beta cubed, etc.
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    (Original post by GarlicBread01)
    I thought the edexcel FP1 book teaches Alpha and Beta way to work out the quadratic equation when given two complex roots?Or are you guys talking about something else
    Yeah I just did a IAL fp1 paper and the alpha and beta questions are a bit different, still possible to do but harder
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    (Original post by GarlicBread01)
    Yeah I just did a IAL fp1 paper and the alpha and beta questions are a bit different, still possible to do but harder
    and won't be on the ordinary FP1 papers.
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    Can I do part b of this question by comparing coefficients? When trying it by comparing coefficients I get different values for the root? Its from the FP1 specimen paper btw.Attachment 524291Name:  ImageUploadedByStudent Room1461139341.871856.jpg
Views: 109
Size:  25.8 KB


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    (Original post by Glavien)
    Can I do part b of this question by comparing coefficients? When trying it by comparing coefficients I get different values for the root? Its from the FP1 specimen paper btw.Attachment 524291Name:  ImageUploadedByStudent Room1461139341.871856.jpg
Views: 109
Size:  25.8 KB


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    Because what you've written isn't true, the coefficient of x^2 on the LHS is 2 and the coefficient of the RHS is 1. So you need to multiply the entirety of the RHS by 2.
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    (Original post by tiny hobbit)
    So make sure that you work through the R papers (and the appropriate questions on the IAL papers).
    Um... so... what are R papers? I am so confused :lol:
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    (Original post by Imperion)
    Um... so... what are R papers? I am so confused :lol:
    "Regional" papers, they have since been replaced by IAL but they were the papers sat by international (non-UK) candidates.
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    (Original post by Zacken)
    Because what you've written isn't true, the coefficient of x^2 on the LHS is 2 and the coefficient of the RHS is 1. So you need to multiply the entirety of the RHS by 2.
    Ohh, thanks.


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    (Original post by Zacken)
    "Regional" papers, they have since been replaced by IAL but they were the papers sat by international (non-UK) candidates.
    Ohhhhhhhhhhhh
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    (Original post by Glavien)
    Ohh, thanks.
    (Original post by Imperion)
    Ohhhhhhhhhhhh
    :cool:
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    How's is everyone's revision going for this module?

    There is just under a month left for the big exam ...
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    (Original post by LelouchViRuge)
    How's is everyone's revision going for this module?

    There is just under a month left for the big exam ...
    Good, just need to work on Matrix equations where numerical methods are not allowed and tricky coordinate system questions.
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    Name:  Rectangular Hyperbola.png
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Size:  78.7 KB

    Part (a) was done with ease, but how do I do part (b), so far I've got;

     x = 6r , y = \frac{6}{r}

    \therefore\frac{dy}{dx} =-\frac{6}{r^2}\cdot\frac{1}{6}

      = -\frac{1}{r^2}

    \therefore m_n = r^2

    I think I have to show somehow that the gradient is the same, so r^2  = -\frac{1}{pq}

    Have I done it right and where do I go from here?
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    (Original post by NotNotBatman)
    ...
    What is the gradient of PR? What is the gradient of QR? What equation can you form linking these two gradients together from the information in the question?

    Then what is the gradient of the normal to H at R, blah blah, you'll figure it out once you do the above.
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    (Original post by NotNotBatman)
    Name:  Rectangular Hyperbola.png
Views: 129
Size:  78.7 KB

    Part (a) was done with ease, but how do I do part (b), so far I've got;

     x = 6r , y = \frac{6}{r}

    \therefore\frac{dy}{dx} =-\frac{6}{r^2}\cdot\frac{1}{6}

      = -\frac{1}{r^2}

    \therefore m_n = r^2

    I think I have to show somehow that the gradient is the same, so r^2  = -\frac{1}{pq}

    Have I done it right and where do I go from here?
    Hey! What paper is this in?? Thanks


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    (Original post by iMacJack)
    Hey! What paper is this in?? Thanks


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    IAL F1 June 2015.
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    (Original post by NotNotBatman)
    IAL F1 June 2015.
    Awesome man - cheers

    How ya feeling about FP1?
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    (Original post by iMacJack)
    Awesome man - cheers

    How ya feeling about FP1?
    Confident for the A, but still need more work for 100 UMS. My teacher is going to give my class the 2015 paper as a mock, so I won't look at it and use it as an indicator for what UMS I will achieve.

    How are you feeling about this exam?
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    (Original post by NotNotBatman)
    Confident for the A, but still need more work for 100 UMS. My teacher is going to give my class the 2015 paper as a mock, so I won't look at it and use it as an indicator for what UMS I will achieve.

    How are you feeling about this exam?
    Same as you! I definitely need to put in work into proof by induction & matrix algebra (going to do the mixed exercises and stuff)

    Yeah the 2015 paper was good! Good luck on it
 
 
 
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