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Edexcel A2 Chemistry Exams -6CH04 (14th June) and 6CH05 (22nd June) Discussion Thread watch

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    (Original post by lfcrules)
    oh **** , i just described recrystallization
    i did recrystallisation as well?
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    (Original post by lfcrules)
    oh **** , i just described recrystallization
    it was recrystallisation
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    (Original post by lfcrules)
    oh **** , i just described recrystallization
    Pretty sure it was recrystallisation as it mentioned the purified 'solid'.
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    on the last question did you protonate both NH2 groups or just the one?
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    (Original post by nicklongy)
    Recrystallisation is correct, it was purifying an impure solid
    Yes!
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    What did everyone do for the vanadium ions 5 marker?
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    YAYYYYYYYY it was recrystalization!!!!!!!!!! . How are you meant to dry the solid , i just mention suction filtration with a buchner funnel and adding anhydrous calcium chloride?
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    which were the conjugate acids and bases?
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    (Original post by Funky_Giraffe)
    on the last question did you protonate both NH2 groups or just the one?
    I protonated both groups . You werent meant to deprotonate the oh group on the molecule with nh2 on were you , just the other molecule was deprotonated?
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    what did you guys put for that wierd benzene mcq , i did the one about ti having a lower enthalpy level or something
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    (Original post by lfcrules)
    I protonated both groups . You werent meant to deprotonate the oh group on the molecule with nh2 on were you , just the other molecule was deprotonated?
    Not sure what you mean. The COOH group would have gone to COO-
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    (Original post by Footyrulez)
    i did recrystallisation as well?
    Oh ****! then
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    (Original post by Footyrulez)
    What did everyone do for the vanadium ions 5 marker?
    First reaction with Iodide ions was feasible to get VO2+, Ecell around +0.46 I think?


    Second reaction was not feasible Ecell -0.20V so remained at V(IV)
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    what was the equation for CuCl2 with HCl and Cu(s) ?
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    feel like you can do both separating funnel and recrystallization, similar q came up ive seen and it was about purification with sodium hdrogencarbonate to remove acid then separate and distill then add anhydrous calcium chloride
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    (Original post by nicklongy)
    First reaction with Iodide ions was feasible to get VO2+, Ecell around +0.46 I think?


    Second reaction was not feasible Ecell -0.20V so remained at V(IV)
    Ah thats what I got as well!!
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    (Original post by lfcrules)
    oh **** , i just described recrystallization
    I did too
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    (Original post by Funky_Giraffe)
    Not sure what you mean. The COOH group would have gone to COO-
    the molecule with the amine groups on also had an oh group on . The oh group didnt lose a proton did it ?
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    5 mark calculation 95.13% anyone?
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    (Original post by Funky_Giraffe)
    what was the equation for CuCl2 with HCl and Cu(s) ?
    Cu2+ + Cu + 4HCl = 2(CuCl2)- + 4H+ ?
 
 
 
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