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Edexcel A2 Chemistry Exams -6CH04 (14th June) and 6CH05 (22nd June) Discussion Thread Watch

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    (Original post by samb1234)
    no problem, I'm just procrastinating to avoid finishing my chem notes anyway haha so glad i could help
    You are procrastinating ? lol, tbh you don't sound like one haha. I'm a bigger one than you
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    (Original post by samb1234)
    It is neither. Both electrodes, technically speaking are negative. Voltage is relative, so essentially the 'positive' electrode is actually negative just not as negative as the other electrode so relative to that electrode is positive

    so just to confirm when you say 'not as negative' you're talking about the charge on the metal electrode itself?
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    Guys can someone tell me if this could be called 2-bromo-1-methylbenzene?Name:  Capture.JPG
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Size:  19.4 KB On wikipedia it said 1-bromo-2-methylbenzene but I don't understand why bromo is on the first carbon?
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    Can someone please explain question 8(a) and (b). I feel like it's a very simple question but i'm just not seeing something:

    http://qualifications.pearson.com/co...e_20150610.pdf
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    (Original post by sabahshahed294)
    You are procrastinating ? lol, tbh you don't sound like one haha. I'm a bigger one than you
    Haha i cant bring myseof to finish them theyre too long (at roughly 200 pages atm lol) so yeah
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    (Original post by samb1234)
    Haha i cant bring myseof to finish them theyre too long (at roughly 200 pages atm lol) so yeah
    Unit 5 is long tbh. 4 is better in this regard. Although I hate NMR Spectroscopy.. :')
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    (Original post by HaydenMoussa)
    Can someone please explain question 8(a) and (b). I feel like it's a very simple question but i'm just not seeing something:

    http://qualifications.pearson.com/co...e_20150610.pdf
    In 8(a), you just add up the enthalpy of both the ions whereas in (b), apply the formula...Enthalpy of Solution= -Lattice Enthalpy plus Enthlapy of Hydration.
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    samb1234 why is the answer to this D?
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    (Original post by Don Pedro K.)
    samb1234 why is the answer to this D?
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    cant be first 2 due to position of the o, c clearly is wrong
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    (Original post by samb1234)
    cant be first 2 due to position of the o, c clearly is wrong
    Position of which O?
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    (Original post by Don Pedro K.)
    Position of which O?
    the O is always to the right of the carbonyl group - if it was a standard carboxylic or acyl chloride you would expect one to be to the right and to the left at the other end
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    (Original post by samb1234)
    the O is always to the right of the carbonyl group - if it was a standard carboxylic or acyl chloride you would expect one to be to the right and to the left at the other end
    Oh wow I just realised I read D as being a dicarboxylic acid when it is actually a hydroxycarboxylic acid (if that's what they're called) xD It makes sense now hahah.

    Oh and also, you can't have two Os at either end of the repeat unit can you?
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    (Original post by Don Pedro K.)
    Oh wow I just realised I read D as being a dicarboxylic acid when it is actually a hydroxycarboxylic acid (if that's what they're called) xD It makes sense now hahah.

    Oh and also, you can't have two Os at either end of the repeat unit can you?
    no you can't as far as i know
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    (Original post by samb1234)
    no you can't as far as i know
    Okay cool, thanks
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    Just checking in here, finished all the past papers now just trying to tide my revision over to the exams
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    (Original post by Whizbox)
    Just checking in here, finished all the past papers now just trying to tide my revision over to the exams
    how were your scores?
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    (Original post by Whizbox)
    Just checking in here, finished all the past papers now just trying to tide my revision over to the exams

    Wow already! Have you tried many IAL papers?
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    Name:  Picture9.jpg
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    is there a easy/ quick way of identifying which reactions are not bronsted lowry acid and bases ? please help x
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  1. File Type: docx Doc3.docx (76.4 KB, 31 views)
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    Hi. Would anyone help out in 18(b)? I never really get this part right so a little elaborate explanation would be helpful. Thanks in Advance!
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    Sorry my bad. Didn't realise that I didn't post the link lol

    https://c838cff4741acb48ae1ed62e5992...0Chemistry.pdf
 
 
 
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