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# Maths question watch

1. Let A = {11,00}. Find A^n for n = 0, 1, and 3
2. (Original post by wdkmwd)
Let A = {11,00}. Find A^n for n = 0, 1, and 3
What is A? The matrix ?

If so consider index laws.
3. (Original post by morgan8002)
What is A? The matrix ?

If so consider index laws.

A is actually a set.

http://postimg.org/image/pmmnuktrd/
4. (Original post by Mathemagicien)
So you want the Cartesian product?

Yes mate.

I would love that
5. (Original post by wdkmwd)
Yes mate.

I would love that
Can you think of what would be?
6. (Original post by wdkmwd)
Yes mate.

I would love that
Oh, and for any set we have .
7. (Original post by Zacken)
Can you think of what would be?

Probably the same thing.

I also think A^0 is 1 isn't it?
8. (Original post by Mathemagicien)
Well, AFAIK, a Cartesian product of two sets A,B is the set of points (x,y) where x is in A, and y is in B

E.g. {a,b}x{c,d}={ (a,c), (a,d), (b,c), (b,d) }

(And thus, as Zacken says, A^0 is the empty set)

Thanks for that, but could you continue?
9. doesn't seem to be uniquely defined, since cartesian product isn't associative.
edit: No, I'm being stupid. Just combine all the elements in 3-tuples.
(Original post by Zacken)
Oh, and for any set we have .
Shouldn't it be , since .
10. (Original post by morgan8002)
doesn't seem to be uniquely defined, since cartesian product isn't associative.
edit: No, I'm being stupid. Just combine all the elements in 3-tuples.

Shouldn't it be , since .
I'm working off this.
11. (Original post by Zacken)
I'm working off this.
Apparently is right and . The second is required for the first, but I'm not sure why the second is true.

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