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    A nebula−a region of the galaxy where new stars are forming−contains a very tenuous gas with 100 atoms/cm3. This gas is heated to 7500 K by ultraviolet radiation from nearby stars.
    What is the pressure, in atm?

    I'm having troubles converting between units. So far my work is:
    pV=nRT so p=nRT/V

    Use avogadro's number to find n=1.66x10^-22

    p=(1.66x10^-22mol)(8.314J/mol K)(7500K)/(1x0^-4m^3)
    p=1.035x10^-13Pa

    This is where I start to get confused.
    1atm=101325Pa
    9.87x10^-6atm=1Pa
    1.035x10^-13Pa=1.02x10^-18atm.
    Is this correct or is there something wrong in the conversions between units?
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    (Original post by PatchworkTeapot)
    A nebula−a region of the galaxy where new stars are forming−contains a very tenuous gas with 100 atoms/cm3. This gas is heated to 7500 K by ultraviolet radiation from nearby stars.
    What is the pressure, in atm?

    I'm having troubles converting between units. So far my work is:
    pV=nRT so p=nRT/V

    Use avogadro's number to find n=1.66x10^-22

    p=(1.66x10^-22mol)(8.314J/mol K)(7500K)/(1x0^-4m^3)
    p=1.035x10^-13Pa

    This is where I start to get confused.
    1atm=101325Pa
    9.87x10^-6atm=1Pa
    1.035x10^-13Pa=1.02x10^-18atm.
    Is this correct or is there something wrong in the conversions between units?
    number of 1 cm cubes in 1 m cube = (number of cm in 1 m)3 and != 1.00x10^4
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    (Original post by Joinedup)
    number of 1 cm cubes in 1 m cube = (number of cm in 1 m)3 and != 1.00x10^4
    So does that mean that the overall pressure is

    p=(1.66x10^-22mol)(8.314J/mol K)(7500K)/(1x10^4m^3)
    p=1.035x10^-21Pa
    p=1.02x10^-26atm?
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    (Original post by PatchworkTeapot)
    So does that mean that the overall pressure is

    p=(1.66x10^-22mol)(8.314J/mol K)(7500K)/(1x10^4m^3)
    p=1.035x10^-21Pa
    p=1.02x10^-26atm?
    moles of gas in 1cm^3 = 1.66e-22
    R=8.314
    T=7500
    V=1/(100^3) = 1.00e-6

    p=nRT/V
    p=(1.66e-22) (8.314) (7500) (1/1.00e-6)
    =1.04e-11 (Pascals)
    =1.03e-16 (atmos)
 
 
 
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